Answer: Required expression: 
Result: 
Step-by-step explanation:
Given phrase: 
Required expression: ['+' used to express sum, 'x' used in place of 'of']
Since 18+16 = 34
Then,
![\dfrac14\times(18+16)=\dfrac14\times34 \\\\=\dfrac{1}{2}\times17\ \ \text{[Divide numerator and denominator by 2]}\\\\=\dfrac{17}{2}](https://tex.z-dn.net/?f=%5Cdfrac14%5Ctimes%2818%2B16%29%3D%5Cdfrac14%5Ctimes34%20%20%5C%5C%5C%5C%3D%5Cdfrac%7B1%7D%7B2%7D%5Ctimes17%5C%20%5C%20%5Ctext%7B%5BDivide%20numerator%20and%20denominator%20by%202%5D%7D%5C%5C%5C%5C%3D%5Cdfrac%7B17%7D%7B2%7D)
Hence, 
13 because absolute is showing the same number but positive
First, let's create an equation for this problem.
($70 × 4) + $40
Now, all you would have to do is solve it using the order of operation (PEMDAS).
($70 × 4) + $40 = $280 + $40
$280 + $40 = $320
The plumber charged $320.
I hope this helps!
Answer:
37 degrees
Step-by-step explanation:
1. m∠CBA = 71+45 = 116 degrees
2. m∠CBA = m∠CDA because of the quadrilateral property of opposite sides.
3. m∠CBA + m∠CDA = 2*116 = 232.
4. Total angle measure of a quadrilateral is 360 degrees, so m∠BAD + m∠BCD = 360-232 = 128 degrees.
5. m∠BAD = m∠BCD = 128/2 = 64 degrees
6. m∠BAC = m∠BAD - m∠CAD = 64 - 27 = 37 degrees
