HELP ASAP I DONT GET IT ITS DUE IN 14 MINS
2 answers:
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Answer: Graph D will be correct graph for the given function.
Explanation:
Given function
Since it is a bi-quadratic equation thus it must have 4 roots and (0,1) is one of its point.
Moreover, the degree of the function is even thus the end behavior of the function is, as
and
as
In graph A, function has four root but it does not have the end behavior same as function f(x).( because in this graph , as
and
, as
.) so, it can not be the graph of given function.
In graph B, neither it has four root nor it has the end behavior same as function f(x).(because in this graph as
and
as
.) so, it can not be the graph of given function.
In graph C, neither it has four root nor it has the same end behavior as function f(x).(because in this graph as
and
as
.) so, it also can not be the graph of given function.
In graph D it has four root as well as it has the same end behavior as the given function. Also it passes through the point (0,1).
Thus, graph D is the graph of given function.