The north displacement and the east displacement can be viewed as simply the legs of a right triangle and the distance between them is just the magnitude of the hypotenuse so:
h^2=x^2+y^2, where h is the distance between the two points, x is the easterly distance and y is the northerly distance....
h^2=.8^2+.6^2
h^2=.64+.36
h^2=1
h=1
So they are one mile apart from each other.
Get a C once every two quarters and you’ll pass my guy
We can set up the width a X and, from the description the length would be 3X-1. The perimeter of a rectangle is determined by 2XL + 2Xw. Plugging into the equation 2(3X-1) + 2(X) = 118. Next distribute to get 6X-2 + 2X = 118. Combine like terms to get 8X = 120. Divide by 8 to get X = 15. The width is 15. The length is 3(15)-1 or 44. 88 +30 = 118
and 7 each time answer Is 78
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