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g100num [7]
3 years ago
14

System of equations, please help.

Mathematics
1 answer:
Rzqust [24]3 years ago
3 0

Answer:

3.75*A + 2.50*D = 35

A + D = 12

A = 12 - D

3.75*(12-D) +2.5*D= 35

45 - 3.75D + 2.5D = 35

45 - 1.25D = 35 |-35

10 - 1.25D = 0 |+1.25D

10 = 1.25D | /1.25

8 = D

A+D=12

A+8=12 |-8

A=4

If you like it, brainliest would be cool

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What transformations was not done to the linear parent function, f(x)=x to get the function g(x)=-1/3(x-7)+2?
Romashka-Z-Leto [24]

Answer:

Step-by-step explanation:

Consider that by changing the the variable x with x-c represents a horizontal shift of c units. If c>0 then it is a right shift and it is a left shift otherwise. When we multiply the variable by a number d (i.e dx) we are applying an horizontal compression/stretching. If d>1 it compresses it, and if 0<d<1 it stretches it. By multipyling the variable x by a negative sign, we are reflecting with respect the x -axis. Finally when we add a number to the function, we are applying a vertical shift.

original function x.

1. (x-7): horizontal shift of 7 units to the right.

2. 1/3(x-7): Horizontal stretching by factor 1/3.

3.-1/3(x-7): Reflection with respect the x-axis

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6 0
3 years ago
Can you come up with denominators that contain variables and aren't equal that would require you to change only one denominator
natali 33 [55]
I think this is what you want.

5 and 10. This would work because 5 goes into 10.

Example: 5, 10, 15, 20
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5 0
3 years ago
Jack leaves school to go home, He walks 6 blocks North and then 8
inysia [295]
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3 years ago
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noname [10]

Answer:

The value of f(9) is equal to 498.

Step-by-step explanation:

Given that,

f(x) = 6x²+12

We need to find the value of x(9).

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f(9) = 6(9)²+12

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So, the value of f(9) is equal to 498.

7 0
3 years ago
F(x, y, z) = yz i + xz j + (xy + 18z) k c is the line segment from (1, 0, −1) to (5, 6, 1) (a) find a function f such that f = ∇
bearhunter [10]
\nabla f(x,y,z)=\dfrac{\partial f}{\partial x}\,\mathbf i+\dfrac{\partial f}{\partial y}\,\mathbf j+\dfrac{\partial f}{\partial z}\,\mathbf k=\mathbf f(x,y,z)

\displaystyle\int\frac{\partial f}{\partial x}\,\mathrm dx=\int yz\,\mathrm dx
\implies f(x,y,z)=xyz+g(y,z)
\dfrac{\partial f}{\partial y}=xz+\dfrac{\partial g}{\partial z}=xz
\implies\dfrac{\partial g}{\partial z}=0
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\dfrac{\partial f}{\partial z}=xy+\dfrac{\mathrm dh}{\mathrm dz}=xy+18z
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6 0
3 years ago
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