System of equations, please help.

Gina decided to order some clothes from a catalog she ordered three pairs of jeans at $39 each for t-shirts at $15 each and 2 st

Blizzard [7]

39 times 3 and 15 times 3 then 27 times 2 then add together to get 216

4 0

3 years ago

Which is the ordered pair for the translated point D'?

olga_2 [115]

$(x;\ y)\\\\D(-3;\ 1)\\\\right(+),\ left(-)\to x\\up(+),\ down(-)\to y\\\\left\ 4\to-3-4=-7\\up\ 0\to1+0=1\\\\Answer:\boxed{D.\ (-7;\ 1)}$

7 0

3 years ago

Read 2 more answers

A cigarette industry spokesperson remarks that current levels of tar are no more than 5 milligrams per cigarette. A reporter doe

d1i1m1o1n [39]

Answer:

$t=\frac{5.63-5}{\frac{1.61}{\sqrt{15}}}=1.516$

$df=n-1=15-1=14$

Since is a right tailed test the p value would be:

$p_v =P(t_{14}>1.516)=0.076$

If we use a significance level of 0.05 we see that $p_v > \alpha$ and then we can conclude that we don't have evidence in order to conclude that the mean is higher than 5.63, so then the claim makes sense.

Step-by-step explanation:

Data given and notation

$\bar X=5.63$ represent the sample mean

$s=1.61$ represent the standard deviation for the sample

$n=15$ sample size

$\mu_o =15/tex] represent the value that we want to test 
[tex]\alpha$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses to be tested

We need to conduct a hypothesis in order to determine if the average is more than 5.63, the system of hypothesis would be:

Null hypothesis: $\mu \leq 5.63$

Alternative hypothesis: $\mu > 5.63$

Compute the test statistic

We don't know the population deviation, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

We can replace in formula (1) the info given like this:

$t=\frac{5.63-5}{\frac{1.61}{\sqrt{15}}}=1.516$

Now we need to find the degrees of freedom for the t distribution given by:

$df=n-1=15-1=14$

P value

Since is a right tailed test the p value would be:

$p_v =P(t_{14}>1.516)=0.076$

If we use a significance level of 0.05 we see that $p_v > \alpha$ and then we can conclude that we don't have evidence in order to conclude that the mean is higher than 5.63, so then the claim makes sense.

3 0

3 years ago

A science teacher has a supply of 50% sugar solution and a supply of 80% sugar solution. How much of each solution should the te

mash [69]

How much of each solution should the teacher mix together to get 105 ML of 60% sugar solution for an experiment?

1. Look at how 60% is closer to the solution of lower concentration (50%). You can deduce that you will be mixing a higher volume of the 50% solution.

2. All 4 answers add up to 105ml.

3. The intuitive answer is the first option:
70 ML of the 50% solution and 35 ML of the 80% solution

4. Let's check whether point 3 is true.
70ml/105ml X 0.5 + 35ml/105ml X 0.8 = (35 + 28)/105= 63/105= 60% / 105 ml = 105ml of 60% sugar solution

3 0

3 years ago

Determine whether the series is convergent or<br> divergent. If it is convergent, find its sum.

Alexandra [31]

Answer:

convergent

Step-by-step explanation:

5 0

3 years ago