Which equation does the graph below represent? y=1/3+x y=1/3x y=3+x y=3x
1 answer:
Lets find 2 points, one obvious one is (0,0), another point is (12,4)
y = mx + b
m is the slope
we got m = 1/3
We can eliminate answer choices C and D.
y = 1/3x + b
we need to solve for b
Plug in the point (0,0) and solve for b
0 = 1/3(0) + b
0 = 0 + b
b = 0
The equation of the line is y = 1/3x + 0, or y = 1/3x
Your answer is B.
y = mx + b
m is the slope
we got m = 1/3
We can eliminate answer choices C and D.
y = 1/3x + b
we need to solve for b
Plug in the point (0,0) and solve for b
0 = 1/3(0) + b
0 = 0 + b
b = 0
The equation of the line is y = 1/3x + 0, or y = 1/3x
Your answer is B.
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Answer:
(x+2)² + (y-3)² = 26
The graphic is showed below
Step-by-step explanation:
The circle equation is given by the expression:
(x-a)² +(y-b)² = r²
The point (a,b) represents the center, and r is the radius. So:
(x+2)² + (y-3)² = r²
If the point A (3,2) is on the circle, then we can replace it in the equation to find r:
(3+2)² + (2-3)² = r²
r² = 5² + (-1)²
r² = 25 + 1
r² = 26
So, the circle has radius r = √26, and the equation is:
(x+2)² + (y-3)² = 26
To graph it, we must put the center C(-2,3), then the radius r = √26 and form a circle, like the figure below.
