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Novay_Z [31]
2 years ago
15

Can someone help me with this pls. I’ll give brainliest

Mathematics
1 answer:
nasty-shy [4]2 years ago
3 0

Answer:

26

Step-by-step explanation:

a triangle is 180 degrees add 120 + 34 to get 154

180 -154 = 26

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Help againnnnnnnnnnnnnnnnnnnnnnnnn
Alexeev081 [22]

Answer:

<h2>10 inches</h2>

Step-by-step explanation:

Hypotenuse = h

h^2 = 8^2 + 6^2

h^2 = 64 + 36

h^2 = 100

h = √100

h = 10

<em>Hope that helps! :)</em>

<em></em>

<em>-Aphrodite</em>

4 0
3 years ago
45 points!<br><br> x+1(8+5)+y2-3(x3+y-4)=36-4+x7-y-1<br> pls i need help now!
Nadya [2.5K]
The answer is X=-2/5
3 0
2 years ago
a company pays its salespeople $2,000 a month and a commission of 18% of their total sales (T). which of the following equations
SSSSS [86.1K]

Answer:

2,360

Step-by-step explanation:

18% of 2,000 is 360

(0.18)*(2,000)=360

2,000 + 360 = 2,360

7 0
3 years ago
A simple random sample of size nequals10 is obtained from a population with muequals68 and sigmaequals15. ​(a) What must be true
valentina_108 [34]

Answer:

(a) The distribution of the sample mean (\bar x) is <em>N</em> (68, 4.74²).

(b) The value of P(\bar X is 0.7642.

(c) The value of P(\bar X\geq 69.1) is 0.3670.

Step-by-step explanation:

A random sample of size <em>n</em> = 10 is selected from a population.

Let the population be made up of the random variable <em>X</em>.

The mean and standard deviation of <em>X</em> are:

\mu=68\\\sigma=15

(a)

According to the Central Limit Theorem if we have a population with mean <em>μ</em> and standard deviation <em>σ</em> and we take appropriately huge random samples (<em>n</em> ≥ 30) from the population with replacement, then the distribution of the sample mean will be approximately normally distributed.

Since the sample selected is not large, i.e. <em>n</em> = 10 < 30, for the distribution of the sample mean will be approximately normally distributed, the population from which the sample is selected must be normally distributed.

Then, the mean of the distribution of the sample mean is given by,

\mu_{\bar x}=\mu=68

And the standard deviation of the distribution of the sample mean is given by,

\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}=\frac{15}{\sqrt{10}}=4.74

Thus, the distribution of the sample mean (\bar x) is <em>N</em> (68, 4.74²).

(b)

Compute the value of P(\bar X as follows:

P(\bar X

                    =P(Z

*Use a <em>z</em>-table for the probability.

Thus, the value of P(\bar X is 0.7642.

(c)

Compute the value of P(\bar X\geq 69.1) as follows:

Apply continuity correction as follows:

P(\bar X\geq 69.1)=P(\bar X> 69.1+0.5)

                    =P(\bar X>69.6)

                    =P(\frac{\bar X-\mu_{\bar x}}{\sigma_{\bar x}}>\frac{69.6-68}{4.74})

                    =P(Z>0.34)\\=1-P(Z

Thus, the value of P(\bar X\geq 69.1) is 0.3670.

7 0
3 years ago
Please help me with this<br> It is due today, so please help me ASAP
horrorfan [7]
1.a. 2 hours 41 minutes b. 10 hours 21 minutes
2.a. 3:10pm b. 12:42pm
4 0
3 years ago
Read 2 more answers
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