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3 years ago

Which of the following is the equation of a line in slope-intercept form for a line with slope = 1/4 and y-intercept at (0, -1)?

Mathematics

1 answer:

NARA [144]3 years ago

6 0

The answer is is D y=1/4x-1

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A scientist measured the width of a square flake of gold to be7.3 x 10 -4mm what is the area of the flake

irakobra [83]

The area of square flake of gold is $53.29 \times 10^{-8} \mathrm{mm}$

<h3><u>Solution:</u></h3>

Given that width of square flake of gold is $7.3 \times 10^{-4}$ millimeter

To find : Area of square flake

Since gold flake is in shape of square, we can use area of square formula

<em><u>The formula for area of square is given as:</u></em>

$area = s^2$

where "s" is the length of one side

$\begin{array}{l}{\text { Area of a square flake }=\left(7.3 \times 10^{-4}\right) \times\left(7.3 \times 10^{-4}\right)} \\\\ {\text { Area of a square flake }=53.29 \times 10^{8}}\end{array}$

Hence , the calculated area of flake is $53.29 \times 10^{-8} \mathrm{mm}$

7 0

2 years ago

PLEASE ANSWER QUICKLY ASAP <br>please read question carefully

puteri [66]

Answer:

340 im pretty sure

Step-by-step explanation:

5 0

3 years ago

The cost of 10 balls is 280. Find the cost of 19 balls.

PSYCHO15rus [73]

Answer:

$532

Step-by-step explanation:

Hey There!

So to solve this problem the first thing that we want to do is find the cost of 1 ball

To do so we divide the total cost of 10 balls by 10

280/10=28 so each ball cost 28

now to find the cost of 19 balls we multiply the cost of 1 ball by 19

18x28=532

thus meaning 19 balls cost $532

8 0

2 years ago

Read 2 more answers

Find the surface area

harkovskaia [24]

The answer is C 210 pi cm^3. Hope this helps

8 0

3 years ago

A = √7 + √c and b = √63 + √d where c and d are positive integers.

mrs_skeptik [129]

Answer:

$\displaystyle a:b=\frac{1}{3}$

Step-by-step explanation:

<u>Ratios </u>

We are given the following relations:

$a=\sqrt{7}+\sqrt{c}\qquad \qquad[1]$

$b=\sqrt{63}+\sqrt{d}\qquad \qquad[2]$

$\displaystyle \frac{c}{d}=\frac{1}{9} \qquad \qquad [3]$

From [3]:

$9c=d$

Replacing into [2]:

$b=\sqrt{63}+\sqrt{9c}$

We can express 63=9*7:

$b=\sqrt{9*7}+\sqrt{9c}$

Taking the square root of 9:

$b=3\sqrt{7}+3\sqrt{c}$

Factoring:

$b=3(\sqrt{7}+\sqrt{c})$

Find the ration a:b:

$\displaystyle a:b=\frac{\sqrt{7}+\sqrt{c}}{3(\sqrt{7}+\sqrt{c})}$

Simplifying:

$\boxed{a:b=\frac{1}{3}}$

3 0

3 years ago