<h3>Given</h3>
4 hundreds flats; 5 tens rods; 2 ones cubes
<h3>Find</h3>
The number of hundreds flats in each of 2 equal piles
<h3>Solution</h3>
When 4 flats are divided into two equal groups, each group will have ...
... 2 flats
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You can imagine doing this the way a card dealer might: first put 1 flat in each of 2 piles, then do the same for the remaining 2 flats. Each pile will end up with 2 flats.
— — — — —
You will have a problem if you continue with the tens rods. There is an odd number of those, so one of them will have to be exchanged for 10 ones cubes.
Number 2 following the angle measures like 90 degress and 180 degress
Step-by-step explanation:
solution
let,A(5,-1)
given
y=12x-1
or, y = 12 × x + (-1)
comparing it with y=mx+c
we get
x=1
y = c = -1
now
A(5,-1) and B(1,-1)
equation of line is,
(y-y1)/(x-x1) = (y2-y1)/(x2-x1)
or, (y+1)/(x-5) = (-1+1)/(1-5)
or, (y+1)/(x-5) = 0/-4
cross multiply
-4y-4 = 0
or, 0=4y+4
or, 4y+4=0 is the required eqn
I think this is the process and answer too.
I hope this helps you
