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Reptile [31]
3 years ago
5

When using base-10 blocks to divide 452 by 2, how many hundreds flats will be in each equal group? hundreds flats Divide 452 by

2 using base-10 blocks - 4 hundreds flats, 5 tens rods, and 2 ones cubes placed side-by-side
Mathematics
1 answer:
daser333 [38]3 years ago
8 0
<h3>Given</h3>

4 hundreds flats; 5 tens rods; 2 ones cubes

<h3>Find</h3>

The number of hundreds flats in each of 2 equal piles

<h3>Solution</h3>

When 4 flats are divided into two equal groups, each group will have ...

... 2 flats

_____

You can imagine doing this the way a card dealer might: first put 1 flat in each of 2 piles, then do the same for the remaining 2 flats. Each pile will end up with 2 flats.

— — — — —

You will have a problem if you continue with the tens rods. There is an odd number of those, so one of them will have to be exchanged for 10 ones cubes.

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If
Anna11 [10]
Answer: -104

Explanation: x=-9 y=2
2(y-3xy)
=2(2-3(-9)(2))
=4-2(3(-18))
=4-108
=-104

Hope it helped

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givi [52]

Answer:

4.5, 4, 3.5, 3, 2.5, 2

Step-by-step explanation:

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Mars2501 [29]

Answer:

i can help with a littel bit of it

Step-by-step explanation:

1. answer

29±95‾‾‾√9

x

=

−

2

9

±

95

i

9

=−0.222222+1.08298

x

=

−

0.222222

+

1.08298

i

=−0.222222−1.08298

x

=

−

0.222222

−

1.08298

i

Find the Solution for:

92+4+11=0

9

x

2

+

4

x

+

11

=

0

using the Quadratic Formula where

a = 9, b = 4, and c = 11

=−±2−4‾‾‾‾‾‾‾‾√2

x

=

−

b

±

b

2

−

4

a

c

2

a

=−4±42−4(9)(11)‾‾‾‾‾‾‾‾‾‾‾‾√2(9)

x

=

−

4

±

4

2

−

4

(

9

)

(

11

)

2

(

9

)

=−4±16−396‾‾‾‾‾‾‾‾‾√18

x

=

−

4

±

16

−

396

18

=−4±−380‾‾‾‾‾√18

x

=

−

4

±

−

380

18

The discriminant 2−4<0

b

2

−

4

a

c

<

0

so, there are two complex roots.

Simplify the Radical:

=−4±295‾‾‾√18

x

=

−

4

±

2

95

i

18

=−418±295‾‾‾√18

x

=

−

4

18

±

2

95

i

18

Simplify fractions and/or signs:

=−29±95‾‾‾√9

x

=

−

2

9

±

95

i

9

which becomes

=−0.222222+1.08298

x

=

−

0.222222

+

1.08298

i

=−0.222222−1.08298

2. Answer:

=−38±895‾‾‾‾√40

x

=

−

3

8

±

895

i

40

=−0.375+0.747914

x

=

−

0.375

+

0.747914

i

=−0.375−0.747914

x

=

−

0.375

−

0.747914

i

3. Answer:

=0=−74

x

=

0

x

=

−

7

4

=0

x

=

0

=−1.75

Find the Solution for

82+14+0=0

8

x

2

+

14

x

+

0

=

0

using the Quadratic Formula where

a = 8, b = 14, and c = 0

=−±2−4‾‾‾‾‾‾‾‾√2

x

=

−

b

±

b

2

−

4

a

c

2

a

=−14±142−4(8)(0)‾‾‾‾‾‾‾‾‾‾‾‾√2(8)

x

=

−

14

±

14

2

−

4

(

8

)

(

0

)

2

(

8

)

=−14±196−0‾‾‾‾‾‾‾√16

x

=

−

14

±

196

−

0

16

=−14±196‾‾‾‾√16

x

=

−

14

±

196

16

The discriminant 2−4>0

b

2

−

4

a

c

>

0

so, there are two real roots.

Simplify the Radical:

=−14±1416

x

=

−

14

±

14

16

=016=−2816

x

=

0

16

x

=

−

28

16

=0=−74

x

=

0

x

=

−

7

4

which becomes

=0

x

=

0

=−1.75

i hope this helps

8 0
2 years ago
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Soloha48 [4]

Answer:

B

Step-by-step explanation:

3 0
3 years ago
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