Answer:
a) D = 4.88 * 10^(-14) m^2 / s
b) <em>t </em>= 1.1 hr
Solution:
a) Magnesium in Aluminum diffusion:
D = Do * exp(-Qd / RT)
= (1.2 * 10^(-4) m^2 / s) * exp ( - 130,000 / 8.31 * 723.15)
= 4.88 * 10^(-14) m^2 / s
D = 4.88 * 10^(-14) m^2 / s
b) The composition remains same at say the distance Xo:
(Cx - Co) / (Cs - Co) = Constant
Xo^2 / D_{550} * <em>t </em>= Xo^2 / D_{450} * 15
D_{550} * <em>t </em>= D_{450} * 15
(1.2 * 10^(-4) m^2 / s) * exp ( - 130,000 / 8.31 * 723.15) * <em>t</em>
(4.88 * 10^(-14) m^2 / s) * 15
by, solving for <em>t </em>we get:
<em>t </em>= 1.1 hr
So, the time required is 1.1 hr.
Organization and access method.
Hope this helped! :)
- Jujufire
Answer:
Explanation:
The following program is written in Java. Using the program code from Purchase class in 5.13 I created each one of the fruit objects. Then I set the price for each object using the setPrice method. Then I set the number of each fruit that I intended on buying with the setNumberBought method. Finally, I called each objects getTotalCost method to get the final price of each object which was all added to the totalCost instance variable. This instance variable was printed as the total cost of the bill at the end of the program. My code HIGHLIGHTED BELOW
//Entire code is in text file attached below.
//MY CODE HERE
DecimalFormat df = new DecimalFormat("0.00");
oranges.setPrice(10, 2.99);
oranges.setNumberBought(2*12);
eggs.setPrice(12, 1.69);
eggs.setNumberBought(2*12);
apples.setPrice(3, 1);
apples.setNumberBought(20);
watermelons.setPrice(1, 4.39);
watermelons.setNumberBought(2);
bagels.setPrice(6, 3.50);
bagels.setNumberBought(12);
totalCost = oranges.getTotalCost() + eggs.getTotalCost() + apples.getTotalCost() + watermelons.getTotalCost() + bagels.getTotalCost();
System.out.println("Total Cost: $" + df.format(totalCost));
}
}
Answer:
Recommended is frame relay architecture with a local loop at each factory supporting the frame relay service connection to the network provider's POP
Explanation:
Frame Relay can be seen as WAN protocol that is said to often operate at both the physical and data layers link of the OSI reference model due to it high-performance and due to the fact that FRAME RELAY are as well use across Integrated Services Digital Network (ISDN) interfaces in which they are designed for cost-efficient data transmission in order to enable effective intermittent traffic between local area networks (LANs) and endpoints in wide area networks (WANs) which is why frame contains all the information necessary to route it to the correct destination.
Therefore type of BN and WAN architecture and WAN service i would recommend based on the above information is FRAME RELAY ARCHITECTURE with a local loop at each factory supporting the frame relay service connection to the network provider's POP.
