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Neko [114]
3 years ago
6

Please help me on this coding problem :)

Computers and Technology
1 answer:
Vesnalui [34]3 years ago
4 0

Answer:

a=4 , b=1

Explanation:

I'm not a computer science major at all but I think I can help you with this code.

Our program wants us to add 2 to a get new a value while also subtracting 1 from b value to obtain new b value. We we want to for for as long b is not 0 and a/b is nonnegative.

One round we get:

New a=0+2=2

New b=3-1=2

Let's see if we can go another round:

New a=2+2=4

New b=2-1=1

We can't go another round because b would be negative while a is positive which would make a/b negative. So our loop stops at this 2nd round.

a=4 , b=1

Other notes:

2nd choice makes no sense because a is always going to increase because of the addition on a and b was going to decrease because of the subtraction on it.

Third choice makes no sense because a/b doesn't even exist.

Fourth choice a/b is negative not nonnegative.

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Ok- well uhm- I need someone's opinion again :')<br> Which one looks better 0.0
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Read 2 more answers
[1] Please find all the candidate keys and the primary key (or composite primary key) Candidate Key: _______________________ Pri
AVprozaik [17]

Answer:

Check the explanation

Explanation:

1. The atomic attributes can't be a primary key because the values in the respective attributes should be unique.

So, the size of the primary key should be more than one.

In order to find the candidate key, let the functional dependencies be obtained.

The functional dependencies are :

Emp_ID -> Name, DeptID, Marketing, Salary

Name -> Emp_ID

DeptID -> Emp_ID

Marketing ->  Emp_ID

Course_ID -> Course Name

Course_Name ->  Course_ID

Date_Completed -> Course_Name

Closure of attribute { Emp_ID, Date_Completed } is { Emp_ID, Date_Completed , Name, DeptID, Marketing, Salary, Course_Name, Course_ID}

Closure of attribute { Name , Date_Completed } is { Name, Date_Completed , Emp_ID , DeptID, Marketing, Salary, Course_Name, Course_ID}

Closure of attribute { DeptID, Date_Completed } is { DeptID, Date_Completed , Emp_ID,, Name, , Marketing, Salary, Course_Name, Course_ID}

Closure of attribute { Marketing, Date_Completed } is { Marketing, Date_Completed , Emp_ID,, Name, DeptID , Salary, Course_Name, Course_ID}.

So, the candidate keys are :

{ Emp_ID, Date_Completed }

{ Name , Date_Completed }

{ DeptID, Date_Completed }

{ Marketing, Date_Completed }

Only one candidate key can be a primary key.

So, the primary key chosen be { Emp_ID, Date_Completed }..

2.

The functional dependencies are :

Emp_ID -> Name, DeptID, Marketing, Salary

Name -> Emp_ID

DeptID -> Emp_ID

Marketing ->  Emp_ID

Course_ID -> Course Name

Course_Name ->  Course_ID

Date_Completed -> Course_Name

3.

For a relation to be in 2NF, there should be no partial dependencies in the set of functional dependencies.

The first F.D. is

Emp_ID -> Name, DeptID, Marketing, Salary

Here, Emp_ID -> Salary ( decomposition rule ). So, a prime key determining a non-prime key is a partial dependency.

So, a separate table should be made for Emp_ID -> Salary.

The tables are R1(Emp_ID, Name, DeptID, Marketing, Course_ID, Course_Name, Date_Completed)

and R2( Emp_ID , Salary)

The following dependencies violate partial dependency as a prime attribute -> prime attribute :

Name -> Emp_ID

DeptID -> Emp_ID

Marketing ->  Emp_ID

The following dependencies violate partial dependency as a non-prime attribute -> non-prime attribute :

Course_ID -> Course Name

Course_Name ->  Course_ID

So, no separate tables should be made.

The functional dependency Date_Completed -> Course_Name has a partial dependency as a prime attribute determines a non-prime attribute.

So, a separate table is made.

The final relational schemas that follows 2NF are :

R1(Emp_ID, Name, DeptID, Marketing, Course_ID, Course_Name, Date_Completed)

R2( Emp_ID , Salary)

R3 (Date_Completed, Course_Name, Course_ID)

For a relation to be in 3NF, the functional dependencies should not have any transitive dependencies.

The functional dependencies in R1(Emp_ID, Name, DeptID, Marketing, Date_Completed) is :

Emp_ID -> Name, DeptID, Marketing

This violates the transitive property. So, no table is created.

The functional dependencies in R2 (  Emp_ID , Salary) is :

Emp_ID -> Salary

The functional dependencies in R3 (Date_Completed, Course_Name, Course_ID) are :

Date_Completed -> Course_Name

Course_Name   ->  Course_ID

Here there is a transitive dependency as a non- prime attribute ( Course_Name ) is determining a non-attribute ( Course_ID ).

So, a separate table is made with the concerned attributes.

The relational schemas which support 3NF re :

R1(Emp_ID, Name, DeptID, Course_ID, Marketing, Date_Completed) with candidate key as Emp_ID.

R2 (  Emp_ID , Salary) with candidate key Emp_ID.

R3 (Date_Completed, Course_Name ) with candidate key Date_Completed.

R4 ( Course_Name, Course_ID ).  with candidate keys Course_Name and Course_ID.

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Answer:

They do anything for money sis

Explanation:

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4 years ago
Write a program that calculates the occupancy rate for ahotel. The program should start by asking the user how many floorsthe ho
Oksana_A [137]

Answer:

Here is the C++ program:

#include <iostream>  //to use input output functions

using namespace std;   //to identify objects like cin cout

int main(){  //start of main function

       int MinFloors = 1;  //minimum number of floors

       int MinRooms  = 10; //minimum number of rooms

       int NoOfFloors;  //stores number of floors

       int NoOfRooms;  //stores number of rooms

       int OccupiedRooms;  //stores number of rooms occupied

       double TotalRooms=0, TotalOccupied=0;   //stores computed total number of rooms and total number of occupied rooms

       cout<<"How many floors does the hotel have? ";  //prompts user to enter number of floors

       do{  //iterates until the user enters valid number of floors

           cout<<"(cannot be less than "<<MinFloors<<"): ";  //error message

           cin >>NoOfFloors;  //reads number of floors from user

       }while(NoOfFloors<MinFloors);  //repeats as long as number of floors is less than minimum number of floors

       for(int floor=1; floor <= NoOfFloors; floor++){    //iterates through the floors to skip third iteration

           if(floor == 3){   //if floor is third floor

               continue;             }  

           cout<<"How many rooms are on floor " <<floor;  //prompts user to enter number of floors

           do{  //start of do while loop

               cout<<"(cannot be less than "<<MinRooms<<"): ";  //error message

               cin >>NoOfRooms;  //reads number of rooms from user

           }while(NoOfRooms<MinRooms);    //iterates as long as number of rooms are less than valid minimum number of rooms

           TotalRooms += NoOfRooms;   //adds number of rooms to the count of total number of rooms

           cout<<"How many of those rooms are occupied?";  //prompts user to enter number of rooms occupied

           do{  //start of do while loop

         cout<<"(cannot be less than 0 or greater than "<<NoOfRooms<<"): ";  //generates error message

         cin >>OccupiedRooms;  //reads number of rooms occupied by user

           }while(OccupiedRooms<0 || OccupiedRooms>NoOfRooms);   //iterates as long as the number of occupied rooms are less than 0 or greater than number of rooms

           TotalOccupied += OccupiedRooms;    }    //adds number of rooms occupied to the count of total number of occupied rooms    

       cout<<"\nThe hotel has a total of "<<TotalRooms<<" rooms"<<endl;  //displays the total number of rooms in the hotel

       cout<<TotalOccupied<<" are occupied."<<endl;  //displays the total number of occupied rooms

       cout<<(TotalRooms-TotalOccupied)<<" are unoccupied."<<endl;  //displays the total number of unoccupied rooms

cout<<"The occupancy rate is: "<<100*(TotalOccupied/TotalRooms)<<"%"<<endl;     }  //computes and displays the occupancy rate

   

Explanation:

The program first prompts the user to enter number of floors in the hotel. Lets say user enters 6. This is stored in NoOfFloors So

NoOfFloors = 6

So the loop runs for 6 times

Next it asks user to enter the number of rooms in the floor 1. Lets say user enters 12 so this is stored in NoOfRooms so

NoOfRooms = 12

TotalRooms += NoOfRooms;

this statement keeps adding number of rooms to TotalRooms so

TotalRooms = 12

Next program asks user about the number of occupied rooms. Lets say user enters 10 so this is stored in OccupiedRooms so

OccupiedRooms = 10

this statement keeps adding number of rooms to TotalOccupied so

 TotalOccupied += OccupiedRooms;

TotalOccupied = 10

At next iteration program asks user again to enter number of rooms in floor 2. Suppose user enters 14 so

NoOfRooms = 12

TotalRooms += NoOfRooms;

TotalRooms = 12+14

TotalRooms = 26

Program asks again to enter number of occupied rooms so it becomes:

OccupiedRooms = 8

this statement keeps adding number of rooms to TotalOccupied so

 TotalOccupied += OccupiedRooms;

TotalOccupied = 10+8

TotalOccupied = 18

Next is skips floor 3 and iteration 3. and asks user to enter number of rooms in floor 4. Suppose user enters 14

Number of rooms become:

TotalRooms = 12+14+14

TotalRooms = 40

and suppose user enters 14 as occupied rooms so total occupied become:

TotalOccupied = 10+8 + 14

TotalOccupied = 32

For floor 5: Suppose user enters 13

TotalRooms = 12+14+14+13

TotalRooms = 53

For floor 5: Suppose user enters 10

TotalOccupied = 10+8 + 14+10

TotalOccupied = 42

For floor 6: Suppose user enters 12

TotalRooms = 12+14+14+13+12

TotalRooms = 65

For floor 6: Suppose user enters 11

TotalOccupied = 10+8 + 14+10+11

TotalOccupied = 53

Now the loop breaks

Hence

TotalRooms = 65

TotalOccupied  = 53

total unoccupied = TotalRooms-TotalOccupied = 65-53 = 12

The occupancy rate is: 100*(TotalOccupied/TotalRooms) = 100*(53/65) = 81.5385

The output of the program is attached in a screenshot.

6 0
4 years ago
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