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Troyanec [42]
3 years ago
11

What is the range of this function

Mathematics
1 answer:
Gwar [14]3 years ago
3 0
I wouldn’t know im sorry
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(If A(2, -3), B(3,-2) and point C divides the line segment AB in the ratio of 1: 2, find OC.)​
Anna007 [38]

Answer:

A(2, -3) and B(3, -2), o(0, 0) Let C(x, y)

Here c divide AB line in the ratio of 1:2

From the line intersection law, we get x=(m1×x2+m2×x1)/(m1+m2)

and y=(m1×y2+m2×y1)/(m1+m2)

where m1=1, m2=2, x1=2, x2=3, y1=-3, y2=-2;

so x=(3+4)/3

  or, x=7/3;

y=(-2-6)/3

 or, y=-8/3;

so, oc=√((0-7/3)²+(0-(-8/3))²)

oc=3.54

7 0
2 years ago
What is the value of x?<br><br><br><br> 3x−8=(8x+4<br> -----<br> 2
stepladder [879]

3x-8 = 8x+4

subtract 3x from each side

-8 = 5x+4

 subtract 4 from each side

-12 = 5x

divide -12 by 5 to get x

x = -12/5 = -2.4

3 0
3 years ago
Which point on the y-axis is on the line that passes through point r and is parallel to line PQ?
Reika [66]

Answer:

(0, Two-thirds)

Step-by-step explanation:

ON edgenuity 2020

8 0
3 years ago
A golf club has 400 members 280 are male 120 are female what fraction of members are female?
Nady [450]

Answer:

3/10 simplified

Step-by-step explanation:

120/400 simplified is 3/10 (divide both numbers by 40).

4 0
3 years ago
∆ABC m∠B = 90° AB = 4 BC = 3<br> Find AC
lutik1710 [3]

Step-by-step explanation:

In ∆ABC, m∠B = 90°

Therefore ∆ABC is a right angled triangle with sides AB = 4 & BC = 3. AC is the hypotenuse.

Hence, by Pythagoras theorem:

AC^2 = AB^2 +BC^2  \\  \\  \therefore \: AC =  \sqrt{AB^2 +BC^2 }  \\  =  \sqrt{ {4}^{2} +  {3}^{2}  }  \\  =  \sqrt{16 + 9}  \\  =  \sqrt{25}  \\  = 5 \\  \\ \huge \red{ \boxed{ \therefore \: AC = 5 \: units}}

8 0
3 years ago
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