Initial velocity of the plane is Vo = 0.
acceleration a = 1.3 m/s2
total distance = 2.5 km = 2500m
time taken to reach 2.5 km with 1.3m/s^2 acceleration = t
S = Vo t + 0.5 a t^2
2500 = 0 + (0.5*1.3* t^2)
t^2 = 3846.15
t = 62 s
the maximum velocity plan can reach within 62 s is Vt
Vt = Vo + a t
Vt = 0 + (1.3*62)
Vt = 80.6 m/s
Since 80.6 m/s is greater than 75 m/s, plane can use this runway to takeoff with required speed.
Answer:
270
Step-by-step explanation:
becasue 100 percent of 90 would be 90

so multiply

Answer:
60°
Step-by-step explanation:
90° = 6x
15° = x
60° = 4x
Answer:
Step-by-step explanation:27/12 - 16/12 = 11/12
Answer:
First Option 
Step-by-step explanation:
To graphically add two vectors a and b using the -tail and tip-method, you must draw the tail of b at the tip of the vector a. Then you must draw a line that goes from the tail of a to the tip of b. This line represents the sum of
.
In this problem, notice that the tail of the vector w is on the tip of the vector v. The line that joins the tail of v with the tip of w is u.
Therefore we can say that
.
The answer is the first option