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zhenek [66]
2 years ago
10

15z-7=14z+12 What does Z equal​

Mathematics
1 answer:
Anika [276]2 years ago
8 0

Answer:

19

Step-by-step explanation:

15z-14z=12+7

z=19

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Does anyone know how to do geometry
olchik [2.2K]
The answer to our question is yes
7 0
3 years ago
2. One angle is one less than six times the measure of
Illusion [34]

The equations used to find the measure of each angle in degrees is x + y = 90 and x = 6y - 1

The two complementary angles are 77 degrees and 13 degrees

<em><u>Solution:</u></em>

Given that two angles are complementary angles

Complementary angles are two angles whose sum is 90 degrees

Let one of the angle be "x" and the other angle be "y"

Therefore,

x + y = 90 ------ eqn 1

Also given that,

One angle is one less than six times the measure of  another

one angle = six times the other angle - 1

x = 6y - 1 ------ eqn 2

Substitute eqn 2 in eqn 1

6y - 1 + y = 90

Thus the above equation is used to find the measure of each angle in degrees

Solve the above equation

6y + y - 1 = 90

7y - 1 = 90

7y = 91

y = 13

Substitute y = 13 in eqn 2

x = 6(13) - 1

x = 78 - 1

x = 77

Thus the two complementary angles are 77 degrees and 13 degrees

8 0
3 years ago
An electric current, I, in amps, is given by I=cos(wt)+√8sin(wt), where w≠0 is a constant. What are the maximum and minimum valu
exis [7]
Take the derivative with respect to t
- w \sin(wt) + \sqrt{8} w cos(wt)
the maximum and minimum values occur when the tangent line is zero so we set the derivative to zero
0 = -w \sin(wt) + \sqrt{8} w cos(wt)
divide by w
0 =- \sin(wt) + \sqrt{8} cos(wt)
we add sin(wt) to both sides

\sin(wt)= \sqrt{8} cos(wt)
divide both sides by cos(wt)
\frac{sin(wt)}{cos(wt)}= \sqrt{8}   \\  \\ arctan(tan(wt))=arctan( \sqrt{8} ) \\  \\ wt=arctan(2 \sqrt{2)} OR\\ wt=arctan( { \frac{1}{ \sqrt{2} } )
(wt)=2(n*pi-arctan(2^0.5))
(wt)=2(n*pi+arctan(2^-0.5))
where n is an integer
the absolute max and min will be

I=cos(2n \pi -2arctan( \sqrt{2} ))
since 2npi is just the period of cos
cos(2arctan( \sqrt{2} ))= \frac{-1}{3} &#10;
substituting our second soultion we get
I=cos(2n \pi +2arctan( \frac{1}{ \sqrt{2} } ))
since 2npi is the period
I=cos(2arctan( \frac{1}{ \sqrt{2}} ))= \frac{1}{3}
so the maximum value =\frac{1}{3}
minimum value =- \frac{1}{3}


4 0
3 years ago
Find the approximate perimeter of rectangle ABCD plotted below.
andre [41]

Answer:

30 unit

I hope I can help

Step-by-step explanation:

i hope I can help

7 0
2 years ago
Find me the value of the variables. If the answers is not an integer, leave it in simplest radical form.
Kruka [31]

Answer:

Step-by-step explanation:

Y=18 and x=9 redical 3

3 0
2 years ago
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