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Deffense [45]
3 years ago
12

Solve the following system of equations:

Mathematics
1 answer:
Talja [164]3 years ago
8 0

Answer:

x=1,y=3

correct answer is (1,3)

Step-by-step explanation:

We can quickly eliminate y by subtracting one equation from the other

(-2x+y=1)-(-4x+y=-1)

2x=2

x=1

plug x=1 into equation 1

-2(1)+y=1

y=1+2=3

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-52 times the difference between a number and 14 is equal to the number plus 3
xenn [34]
X=number looked for
we have this equation:
-52(x-14)=x+3
we solve this equation:
-52x+728=x+3
-52x-x=3-728
-53x=-725
x=-725/-53=725/53 ≈13,68

Solution: 725/53

To check:
the difference between 725/53 and 14=725/53  - 14=(725-742)/53=-17/53
-52 times the diference is= -52(-17/53)=884/53
The number plus 3=725/53 + 3=(725+159)/53=884/53
3 0
3 years ago
The cost is $6.75 for 1 item. Find the cost of 8 items
scoray [572]

Answer:

$54

Step-by-step explanation:

Multiply the cost by the number of items

6.75x8=54

The cost is $54

5 0
3 years ago
Read 2 more answers
F(m) = 6m - 5<br> g(m) = 3m - 6
Anastaziya [24]

Answer:

what is the question. please provide a question.

3 0
2 years ago
Calculate the loan for $10,000, at an annual percentage rate of 5%, for a term of 5 years. What is the amount of accrued interes
nikdorinn [45]

Answer:

Step-by-step explanation:

<em>I= </em><em>P*r*T</em>

<em>Interest equals 10,000 times 5% times 5 years</em>

<em>$2500  is the total interest.</em>

4 0
3 years ago
The average American man consumes 9.8 grams of sodium each day. Suppose that the sodium consumption of American men is normally
Alex Ar [27]

Answer:

(a) The distribution of <em>X</em> is <em>N</em> (9.8, 0.8²).

(b) The probability that an American consumes between 8.8 and 9.9 grams of sodium per day is 0.4461.

(c) The middle 30% of American men consume between 9.5 grams to 10.1 grams of sodium.

Step-by-step explanation:

The random variable <em>X</em> is defined as the amount of sodium consumed.

The random variable <em>X</em> has an average value of, <em>μ</em> = 9.8 grams.

The standard deviation of <em>X</em> is, <em>σ</em> = 0.8 grams.

(a)

It is provided that the sodium consumption of American men is normally distributed.

The random variable <em>X</em> follows a normal distribution with parameters <em>μ</em> = 9.8 grams and <em>σ</em> = 0.8 grams.

Thus, the distribution of <em>X</em> is <em>N</em> (9.8, 0.8²).

(b)

If X ~ N (µ, σ²), then Z=\frac{X-\mu}{\sigma}, is a standard normal variate with mean, E (Z) = 0 and Var (Z) = 1. That is, Z ~ N (0, 1).

To compute the probability of  Normal distribution it is better to first convert the raw score (<em>X</em>) to <em>z</em>-scores.

Compute the probability that an American consumes between 8.8 and 9.9 grams of sodium per day as follows:

P(8.8

                           =P(-1.25

Thus, the probability that an American consumes between 8.8 and 9.9 grams of sodium per day is 0.4461.

(c)

The probability representing the middle 30% of American men consuming sodium between two weights is:

P(x_{1}

Compute the value of <em>z</em> as follows:

P(-z

The value of <em>z</em> for P (Z < z) = 0.65 is 0.39.

Compute the value of <em>x</em>₁ and <em>x</em>₂ as follows:

-z=\frac{x_{1}-\mu}{\sigma}\\-0.39=\frac{x_{1}-9.8}{0.8}\\x_{1}=9.8-(0.39\times 0.8)\\x_{1}=9.488\\x_{1}\approx9.5     z=\frac{x_{2}-\mu}{\sigma}\\0.39=\frac{x_{1}-9.8}{0.8}\\x_{1}=9.8+(0.39\times 0.8)\\x_{1}=10.112\\x_{1}\approx10.1

Thus, the middle 30% of American men consume between 9.5 grams to 10.1 grams of sodium.

4 0
3 years ago
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