Question

Question 4 (1 point) Lola and Keegan auditioned for the talent show. They decided to rap a new song. Keegan would sing every 8 seconds and Lola would sing every 14 seconds. If they sang together at the 2 minute and 10 second mark, when will they sing together again? They will sing together again at the min second mark.

Answer 1

Answer:

56th second

Step-by-step explanation:

Given

$Lola = Every\ 8\ seconds$

$Keegan = Every\ 14\ seconds$

$Time = 2\ minutes\ 10\ seconds$

Required

Determine when they sing together

First, we convert the total time to seconds.

$Time = 2\ minutes\ 10\ seconds$

$Time = 2 * 60\ seconds + 10\ seconds$

$Time = 120\ seconds + 10\ seconds$

$Time = 130\ seconds$

Next, we determine the Least Common Multiple of Lola and Keegan's time:

Lola:

$8\ seconds = 8, 16, 24, 32, 40, 48, 56, 64, 72, 80, 88, 96, 104, 112, 120, 128$

Keegan:

$14\ seconds = 14, 28, 42, 56, 70, 84, 98, 112, 126$

The least common multiple is 56. Hence, they will sing together at the 56th second