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sergejj [24]
4 years ago
10

Help meh I will give brainiest!! Answer as much as you know.

Mathematics
1 answer:
coldgirl [10]4 years ago
4 0

Here i did this to. Hope it helps! It wont let me download it so I am just gonna put them on here.

Unit 7 Review Guided Notes Page

Question 1

Find the missing side length.

5*5=25+ 7*7=49= 74 so 8.6

Question 2

What is the area of the parallelogram?

18*50=900

Question 3

What is the perimeter of the figure?

If you break the object apart. 7+7+1+1=16

5+5+3+3=16

16+16=32m

Question 4

What are the solutions to the equation?

x^2 – 22 = 14

I found that 6*6=36 – 22=14

I tried a few numbers .

Question 5

What is the area of the figure?

If you break the figure apart. 3*2=6

2*6=12

6+12=18cm

Question 6

What is the area of the trapezoid?

11+3=14*9=126*2=252

Question 7

Hint: 1 Revolution equals the Circumference!

How far does a wheel travel in 2 revolutions if it has a radius of 45 cm?

2*3.14=6.28*45=282.6*2=565.2

Question 8

The diameter of the larger circle is 11 cm.  The diameter of the smaller circle is 7 cm.  What is the area approximate area of the shaded region?

For the smaller one – 7/2= 3.5 *3.5*3.14=38.46

For the bigger one- 5.5*5.5*3.14=94.98

94.98-38.46=56.52

Question 9

What is the approximate area of a circular garden that has a diameter of 12 feet?

A= Pi*r2. 3.14*6^2 =113

6*6=36*3.14= 113.04

Question 10

A 17-foot pole is leaning against a wall.  The bottom of the pole is 8 feet away from the bottom of the wall.  Approximately how high up the wall does the top of the pole reach?

(a^2+b^2=c^2) Its 15 ft

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Which of the follwing is correxr
agasfer [191]

Answer:

the equation has infinitely amny solutions

3 0
3 years ago
What is the number nearest to 10000 which is exactly divisible by 3, 4, 5, 6, 7, and 8?.
Tems11 [23]

10080 is the number nearest to 10000 that is divisible by 3, 4, 5, 6, 7, and 8.

Divisibility is being able to divide a number evenly and result to a whole number. Divisibility rules are set of rules to test if one number is divisible by another without doing much computation.

#1: divisibility by 2

A number is divisible by 2 if its last digit is even.

# 2: divisibility by 3:

A number is divisible by 3 if the sum of its digits is divisible by 3.

# 3: divisibility by 4

A number is divisible by 4 if the number represented by its last two digits is divisible by 4.

#4: divisibility by 5

A number is divisible by 5 if its last digit is 0 or 5.

# 5: divisibility by 6

A number is divisible by 6 if it is divisible by both 2 and 3.

# 6: divisibility by 7

Double the last digit and subtract it from a number made by the other digits. The result must be divisible by 7.

#7: divisibility by 8

A number is divisible by 8 if the number represented by its last three digits is divisible by 8.

#8: divisibility by 9

A number is divisible by 9 if the sum of its digits is divisible by 9.

# 9: divisibility by 10

A number is divisible by 10 if its last digit or the digit in the ones place is 0.

To get the number nearest to 10000 that is divisible by 3, 4, 5, 6, 7, and 8, consider first the numbers that are divisible by 5(numbers ending in 5 or 0) and narrow it down to numbers ending in 0 since numbers ending in 5 is not divisible by 2, thus making it indivisible by 6.

The process goes on by narrowing the list by checking its divisibility by 3, 4, 7 and 8.

To know more about divisibility rules, visit brainly.com/question/9462805.

#SPJ4

7 0
1 year ago
Solve/ Find x<br><br><br><br><br> -3(x+7)+2(x-2)
butalik [34]

Answer:

Step-by-step explanation:

-3x - 21 + 2x -4

-x - 25

-(x + 25)

7 0
3 years ago
f(x) = x4 - 50x2 + 3 (a) Find the intervals on which f is increasing. (Enter the interval that contains smaller numbers first.)
shtirl [24]

Answer:

  (-5, 0) ∪ (5, ∞)

Step-by-step explanation:

I find a graph convenient for this purpose. (See below)

__

When you want to find where a function is increasing or decreasing, you want to look at the sign of the derivative. Here, the derivative is ...

  f'(x) = 4x^3 -100x = 4x(x^2 -25) = 4x(x +5)(x -5)

This has zeros at x=-5, x=0, and x=5. The sign of the derivative will be positive when 0 or 2 factors have negative signs. The signs change at the zeros. So, the intervals of f' having a positive sign are (-5, 0) and (5, ∞).

5 0
3 years ago
Can someone please help me with this last one. I am totally lost and don’t understand
Ad libitum [116K]

Answer:

g(-4) = -1

g(-1) = -1

g(1) = 3

Explanation:

If you are given a function that is defined by a system of equations associated with certain intervals of x, just find which interval makes x true, and then substitute x into the equation of that interval.

For example, given g(-4), this is an expression which is asking for the value of the equation when x = -4. So -4 is not ≥ 2, so ¼x - 1 will not be used. -4 is also not ≤ -1 and ≤ 2, so -(x - 1)² + 3 will not be used either. So in turn, we will just use -1 which is always -1 so g(-4) will just be -1, right because there is no x variable in -1 so it will always be the same.

Using the same idea as before g(-1) is g(x) when x = -1 so -1 will not be a solution because -1 is not less than -1 (< -1). -1 is not ≥ 2 either so we will be using the second equation because -1 is part of the interval -1≤x≤2 (it is a solution to this inequality), therefore -(x - 1)² + 3 will be used.

As x = -1, -(x - 1)² + 3 = -(-1 - 1)² + 3 = -(-2)² + 3 = -4 + 3 = -1.

It is a coincidence that g(-1) = -1.

Now for g(1), where g(x) has an input of 1 or the value of the function where x = 1, we will not use the first equation because x = 1 → x < -1 → 1 < -1 [this is false because 1 is never less than -1], so we will not use -1.

We will use -(x - 1)² + 3 again because 1 is not ≥ 2, 1≥2 [this is also false]. And -1 ≤ 1 < 2 [This is a true statement]. Therefore g(1) = -(1 - 1)² + 3 = -(0)² + 3 = 3

4 0
3 years ago
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