A book 2meters I found it so yea I concert and did a
That so that's your answer ya good now or nah ok good contact meh if u need help huh bye
Answer:
Step-by-step explanation:
Question
Find the perimeter of a triangle with vertices A(2,5) B(2,-2) C(5,-2). Round your answer to the nearest tenth and show your work.
perimeter of a triangle = AB+AC+BC
Using the distance formula
AB = sqrt(-2-5)²+(2-2)²
AB = sqrt(-7)²
AB =sqrt(49)
AB =7
BC = sqrt(-2+2)²+(2-5)²
BC = sqrt(0+3²)
BC =sqrt(9)
BC =3
AC= sqrt(-2-5)²+(2-5)²
AC= sqrt(-7)²+3²
AC =sqrt(49+9)
AC =sqrt58
Perimeter = 10+sqrt58
Answer:
192y^8
Step-by-step explanation:
9514 1404 393
Answer:
(6.2, 4.5)
Step-by-step explanation:
We want, for some point P, ...
(P -A) / (B -P) = 1 / 3
3(P -A) = (B - P) . . . . . multiply by 3
4P = B +3A . . . . . . . . add P+3A
P = (B +3A)/4 . . . . . . .divide by 4
Filling in the coordinate values, we can find P to be ...
P = ((2.3, 5.4) +3(7.5, 4.2))/4 = (2.3+22.5, 5.4+12.6)/4
P = (6.2, 4.5)
