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3 years ago

The cone in the diagram below has a radius of 10 mm and its height is 24 mm.

Mathematics

2 answers:

Amiraneli [1.4K]3 years ago

7 0

Slant height l is 26 mm

svp [43]3 years ago

3 0

The slant height for “L” should be 26mm

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An engineering scale model shows a church that is 2 inches tall. if the scale is 1 inch = 256 feet, how tall is the actual churc

SVETLANKA909090 [29]

Answer:

Actual height of church = 512 feet

Step-by-step explanation:

Given:

Scale model;

1 inch = 256 feet

Height of church (Scale model) = 2 inches

Find:

Actual height of church

Computation:

Actual height of church = Height of church (Scale model) x scale length

Actual height of church = 2 inches x 256 feet/inches

Actual height of church = 2 x 256 feet

Actual height of church = 512 feet

8 0

3 years ago

Karen has 7 over 8cup of ice cream. How many 1 over 3cup servings can she make?

STALIN [3.7K]

Answer:

1 and 5 over 24

Step-by-step explanation:

its right trust me because 1+1 is 3

8 0

3 years ago

During the spring and summer months, the Happy Home Motel sees a rise in travelers. The manager of the motel turned in this repo

Korvikt [17]

Answer:

342

Step-by-step explanation:

Let's see the difference is each successive values:

232 - 217 = 15

252 - 232 = 20

277 - 252 = 25

307 - 277 = 30

As we can see, each month the increase is 5 more than previous months' increase. Clearly from the pattern we can surmise that the next month (August), it will increase by 35 from the value of July.

Number of visitors in August = Number of Visitors in July + 35 = 307 + 35 = 342

4 0

3 years ago

Read 2 more answers

In ΔQRS, the measure of ∠S=90°, the measure of ∠R=29°, and SQ = 5.8 feet. Find the length of RS to the nearest tenth of a foot.

taurus [48]

Answer:

10.5 ft

Step-by-step explanation:

In ΔQRS,

m∠S=90°
m∠R=29°,
SQ = 5.8 feet.

See the diagram below.

The triangle is a Right Triangle,

Using trigonometric ratios,

$Tan R=\dfrac{|SQ|}{|RS|} \\Tan 29^\circ=\dfrac{5.8}{|RS|}\\$Cross multiply$\\|RS|XTan 29^\circ=5.8\\|RS|=\dfrac{5.8}{Tan 29^\circ}\\$=10.5 ft (to the nearest tenth of a foot)$