We want to find one-half of the reciprocal of 7/sqrt(98). Let's write down an expression for this:
We can rewrite 98 into 
The square root of 49 is 7
This should be your answer. Let me know if you need any clarifications, thanks!
Answer:
10,404/334,084
Step-by-step explanation:
Given the polynomial
289r^2 - 102r + c
We are to find the value of c that will make it a perfect square
Divide through by 289
289r²/289 - 102r/289 + c/289
Half of the coefficient of r is 1/2(102/289)
Half of the coefficient of r = 102/578
Square the result
r² = (102/578)²
r² = 10,404/334,084
Hence the required constant is 10,404/334,084
$4004 just take 48048 and divide that by 12 to get your answer
Answer: Substitution
Step-by-step explanation:
Because you know A is equal to B, you can substitute A for B in any mathematical equation. Essentially, you are switching mA $ mB.
