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Dafna1 [17]
2 years ago
7

Amir buys a coat that cost $125.00. He has to pay 6.25% state tax on the coat. He also has to pay 2.0% local tax on the cost.Wha

t is the total amount that he has to pay?
F)$133.25
G) $133.88
H)$135.31
J)$135.47
Mathematics
1 answer:
gulaghasi [49]2 years ago
3 0

Answer: $133.8

Step-by-step explanation:

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A product is composed of four parts. In order for the product to function properly in a given situation, each of the parts must
nirvana33 [79]

Answer:

0.430

Step-by-step explanation:

Product has four parts :

For proper functioning, each part must function :

Let the 4 parts be:

A, B, C and D

Proper functioning probability :

A and B = 0.79

C and D = 0.83

For proper functioning :

P(A) * P(B) * P(C) * P(D)

0.79 * 0.79 * 0.83 * 0.83

= 0.42994249

= 0.430

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3 years ago
What is 1189^2 x 1809
Trava [24]

Answer:

the answer is : 2557421289

8 0
3 years ago
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Use the product, quotient, and power rules of logarithms to rewrite the expression as a single logarithm. Assume that all variab
Viefleur [7K]

Answer:

log(x^7·y^2)

Step-by-step explanation:

The applicable rules are ...

... log(a^b) = b·log(a)

... log(ab) = log(a) +log(b)

_____

The first term, 7log(x) can be rewritten as log(x^7). Note that an exponentiation operator is needed when this is written as text.

The second term 2log(y) can be rewritten as log(y^2). These two rewrites make use of the first rule above.

Now, you have the sum ...

... log(x^7) +log(y^2)

The second rule tells you this can be rewritten as ...

... log(x^7·y^2) . . . . . seems to match the intent of the 3rd selection

5 0
3 years ago
I'm confused about this question
lesantik [10]

Answer:

the answer is 3

Step-by-step explanation:

4 0
3 years ago
Find the solution of the initial value problem<br><br> dy/dx=(-2x+y)^2-7 ,y(0)=0
Leokris [45]

Substitute v(x)=-2x+y(x), so that \dfrac{\mathrm dv}{\mathrm dx}=-2+\dfrac{\mathrm dy}{\mathrm dx}. Then the ODE is equivalent to

\dfrac{\mathrm dv}{\mathrm dx}+2=v^2-7

which is separable as

\dfrac{\mathrm dv}{v^2-9}=\mathrm dx

Split the left side into partial fractions,

\dfrac1{v^2-9}=\dfrac16\left(\dfrac1{v-3}-\dfrac1{v+3}\right)

so that integrating both sides is trivial and we get

\dfrac{\ln|v-3|-\ln|v+3|}6=x+C

\ln\left|\dfrac{v-3}{v+3}\right|=6x+C

\dfrac{v-3}{v+3}=Ce^{6x}

\dfrac{v+3-6}{v+3}=1-\dfrac6{v+3}=Ce^{6x}

\dfrac6{v+3}=1-Ce^{6x}

v=\dfrac6{1-Ce^{6x}}-3

-2x+y=\dfrac6{1-Ce^{6x}}-3

y=2x+\dfrac6{1-Ce^{6x}}-3

Given the initial condition y(0)=0, we find

0=\dfrac6{1-C}-3\implies C=-1

so that the ODE has the particular solution,

\boxed{y=2x+\dfrac6{1+e^{6x}}-3}

5 0
3 years ago
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