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gayaneshka [121]
3 years ago
11

Which of the shaded regions below represents 3/5 of the whole circle

Mathematics
1 answer:
Norma-Jean [14]3 years ago
3 0

Answer: B

Step-by-step explanation:

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we need help? can somebody answer this question

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Which figure has exacly 2 sets of parallel sides and no perpendicular sides
sweet-ann [11.9K]
Square. Because there is 2 right angles there are only 4 sides all which are perpendicular
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3 years ago
Which graph represents f(x)=log3x 1?
exis [7]

The correct option A: graph A, shows the logarithmic function;

f(x) = log₃x + 1

<h3>Explain the term logarithmic function?</h3>
  • The opposite of such an exponential function is a logarithmic function.
  • A log function and then an exponential function both use the same base.
  • An exponent is a logarithm. f(x) = bx is how the exponential function be expressed.
  • The formula again for logarithmic function is f(x) = log base b of x.

f(x) = log₃x + 1

  • When x = 1

f(1) = log₃1 + 1

f(1) = 0 + 1

f(1) = 1

(1, 1)

  • When x = 3

f(3) = log₃3 + 1

f(3) = 1 + 1

f(3) = 2

(3, 2)

Thus, the graph must contain the points   (1, 1), (3, 2).

Therefore, graph A define the given logarithmic function;

f(x) = log₃x + 1.

To know more about the logarithmic function, here

brainly.com/question/13473114

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7 0
1 year ago
How much more pizza is in a 12-in.diameter pizza than an 8-in.diameter pizza?
e-lub [12.9K]

Answer:

62.8 in2

Step-by-step explanation:

With round pizza we need to

find the area of each pizza in

square inches, then determine

the difference.  

The area of a circle is given by:

A = πr2

 

12 inch diameter, radius = 6

a = π(62) = 36π in2

 

8 inch diameter, radius = 4

a = π(42) = 16π in2

 

Difference:  36π - 16π = 20π in2

 

using 3.14 for pi, the difference is

20(3.14) = 62.8 in2

3 0
3 years ago
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What is the asymptote for the graph of this logarithmic function?<br><br> f(x) = log3(x – 1)
Pepsi [2]

Answer:

Vertical Asymptote:

x=1

Horizontal asymptote:

it does not exist

Step-by-step explanation:

we are given

f(x)=log_3(x-1)

Vertical asymptote:

we know that vertical asymptotes are values of x where f(x) becomes +inf or -inf

we know that any log becomes -inf when value inside log is zero

so, we can set value inside log to zero

and then we can solve for x

x-1=0

we get

x=1

Horizontal asymptote:

we know that

horizontal asymptote is a value of y when x is +inf or -inf

For finding horizontal asymptote , we find lim x-->inf or -inf

\lim_{x \to \infty}  f(x)= \lim_{x \to \infty}log_3(x-1)

\lim_{x \to \infty}  f(x)=log_3(\infty-1)

\lim_{x \to \infty}  f(x)=undefined

so, it does not exist

7 0
3 years ago
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