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2 years ago

Evaluate n+2x^2 when n=3 and x=-2

Mathematics

1 answer:

hram777 [196]2 years ago

7 0

Answer:

11 is your answer.

Step-by-step explanation:

We have the equation: n + 2x^2

We know that n = 3 and x = -2

Substitute the variables for their values.

3 + 2(-2)^2 = ?

Then just solve to get 11.

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In the song, 25 percent of the class weighed less than 6 pounds, 1 ounce at birth. 6 pounds, 1 ounce is the

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3 years ago

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Riley's monthly bank statement showed the following deposits and withdrawals:

pshichka [43]

Answer:

$159.09

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2 years ago

A roast turkey is taken from an oven when its temperature has reached 185 degrees F and is placed on a table in a room where the

Vedmedyk [2.9K]

(a) Using Newton's Law of Cooling, $\dfrac{dT}{dt} = k(T - T_s)$ , we have $\dfrac{dT}{dt} = k(T - 75)$ where T is temperature after T minutes.
Separate by dividing both sides by T - 75 to get $\dfrac{dT}{T - 75} = k dt$ . Integrate both sides to get $\ln|T - 75| = kt + C$ .

Since $T(0) = 185$ , we solve for C:
$|185 - 75| = k(0) + C\ \Rightarrow\ C = \ln 110$
So we get $\ln|T - 75| = kt + \ln 110$ . Use T(30) = 150 to solve for k:
$\ln| 150 - 75 | = 30k + \ln 110\ \Rightarrow\ \ln 75 - \ln 110= 30k \Rightarrow \\ k= \frac{1}{30}\ln (75/110) = \frac{1}{30}\ln(15/22)$

So

$\ln|T - 75| = kt + \ln 110 \Rightarrow |T - 75| = e^{kt + \ln110} \Rightarrow \\ \\
|T - 75| = 110e^{kt} \Rightarrow T - 75 = \pm110e^{(1/30)\ln(15/22)t} \Rightarrow \\
T = 75 \pm110e^{(1/30)\ln(15/22)t}$

But choose Positive because T > 75. Temp of turkey can't go under.

$T(t) = 75 + 110e^{(1/30)\ln(15/22)t} \\
T(45) = 75 + 110e^{(1/30)\ln(15/22)(45)} = 136.929 \approx 137{}^{\circ}F$

(b)

$T(t) = 75 + 110e^{(1/30)\ln(15/22)t} = 75 + 110(15/22)^{t/30} \\
100 = 75 + 110(15/22)^{t/30} \\
25 = 110(15/22)^{t/30} 
\frac{25}{110} = (15/22)^{t/30} \\
\ln(25/110) / ln(15/22) = t/30 \\
t = 30\ln(25/110) / ln(15/22) \approx 116\ \mathrm{min}$

Dogs of the AMS.

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3 years ago

The speed that a tsunami can travel is modeled by the equation s = 356 startroot d endroot , where s is the speed in kilometers

Naddika [18.5K]

The approximate depth of water for a tsunami traveling at 200 kilometers per hour is 0.32 km.

<h3>What is speed?</h3>

Speed can be calculated as the ratio of distance traveled to the time taken.

The speed that a tsunami can travel is modeled by the equation

s = 356√d, where s is the speed in kilometers per hour and d is the average depth of the water in kilometers.

S = 356√d

200 = 356√d

√d = 200/356

= 0.5618

d = 0.5618^2

= 0.316 km

d = 0.32 km.

Thus, The approximate depth of water for a tsunami traveling at 200 kilometers per hour is 0.32 km.

Learn more about speed;

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2 years ago

Help MOI for the Third time PLS<br> Solve for t.<br><br> –9t − 19t + 9t − –18t − t = 14

Lorico [155]

Answer:

–9t − 19t + 9t − –18t − t = 14

t = -7

Step-by-step explanation:

Hope this helps!!

3 0

3 years ago