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Ostrovityanka [42]

3 years ago

15

plzzzzzzzzzzzzzzzzzzzzzzzzzz help plz i really wanna pass this semster so i can go to 10th gradeee im begging plz helpppppppp wi

ll mark brainlist

1 answer:

Naily [24]3 years ago

7 0

Answer:

<em>The</em><em> </em><em>answer</em><em> </em><em>is</em><em> </em><em>x</em><em> </em><em>-</em><em> </em><em>y</em><em> </em><em>=</em><em> </em><em>7</em>

Step-by-step explanation:

<em>2x</em><em> </em><em>-</em><em> </em><em>2y</em><em> </em><em>=</em><em> </em><em>14</em><em> </em>

<em>2</em><em>(</em><em>x</em><em> </em><em>-</em><em> </em><em>y</em><em>)</em><em> </em><em>=</em><em> </em><em>14</em><em> </em>

<em>x</em><em> </em><em>-</em><em> </em><em>y</em><em> </em><em>=</em><em> </em><em>14</em><em>/</em><em>2</em>

<em>x</em><em> </em><em>-</em><em> </em><em>y</em><em> </em><em>=</em><em> </em><em>7</em><em> </em>

<em>PLEASE</em><em> </em><em>THANK</em><em>,</em><em> </em><em>RATE</em><em> </em><em>AND</em><em> </em><em>FOLLOW</em><em> </em><em>ME</em><em>,</em>

<em>AND</em><em> </em><em>PLEASE</em><em> </em><em>MARK</em><em> </em><em>ME</em><em> </em><em>AS</em><em> </em><em>"</em><em>BRAINLIEST</em><em>"</em><em> </em><em>ANSWER</em><em> </em>

<em>HOPE</em><em> </em><em>IT</em><em> </em><em>HELPS</em><em> </em><em>YOU</em><em> </em>

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Match each expression in the left column with the correct product in the right column.

lesya692 [45]

Answer:

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Step-by-step explanation:

1) √4 . √-3 . √-3

$\sqrt{4} = 2$

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$\sqrt{4} . (\sqrt{-3})^2 = 2 \times -3 =$ -6

2) √-4 . √-3 . √-3

$\sqrt{-4} = 2i$ .

Therefore, $\sqrt{-4} . \sqrt{-3} . \sqrt{-3} = 2. \sqrt{-1} \times -3 = 2i \times (-3) =$ - 6i

3) √4 . √3 . √-3

$\sqrt{4} = 2$

$\sqrt{3} . \sqrt{-3} = (\sqrt{3})^2 . \sqrt{-1}$

$\implies 2 \times 3i =$ 6i

4) √4 . √3 . √3

$\sqrt{4} = 2$

$\sqrt{3} . \sqrt{3} = (\sqrt{3})^2 = 3$

Therefore, √4 . √3 . √3 = 2 . 3 = 6

5 0

3 years ago

In the diagram, point O is the center of the circle and m∠ADB = 43°. If m∠AOB = m∠BOC, what is m∠BDC?

Sladkaya [172]

Answer:

m∠BDC = 43°

Step-by-step explanation:

According to the theorem every peripheral angle in the circle is equal to half value of central angle.

Angle m∠ADB is corresponding peripheral angle of central angle m∠AOB.

According to this m∠AOB = 2· m∠ADB = 2· 43 = 86°

If angle m∠BOC=m∠AOB= 86°

Angle m∠BDC is corresponding peripheral angle of central angle m∠BOC

According to this m∠BDC = m∠BOC/2 = 43°

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