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Leviafan [203]
2 years ago
6

5(2 + 5) = 6 − 10 – solve for x please show your work

Mathematics
1 answer:
frez [133]2 years ago
8 0
I don’t know -4 maybe
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Find the measure of a 6.<br> 102<br> 78<br> 46 = [?]
Rom4ik [11]

Answer:

102°

Step-by-step explanation:

They're still corresponding angles... have you read any of these explanations?...

6 0
2 years ago
Hoping someone will help me out
pogonyaev

Answer:

It does not converge

Step-by-step explanation:

7 0
3 years ago
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If angle DAB measures 34 degrees, what is the measure of arc DB
ollegr [7]
Arc DB will also measure 34 degrees.
4 0
3 years ago
Which statement correctly names the congruent triangles and justifies the reason for congruence?
Marat540 [252]

Answer:

  C. Triangle BAC is congruent to triangle FDE by AAS

Step-by-step explanation:

BAC names the vertices in the order longest-side, shortest-side. That same order is FDE in the other triangle, eliminating choiced B and D. The triangles are not right triangles, eliminating choice A.

The only viable answer choice is C.

No specific sides are shown as being congruent, but two angles are, so we could claim congruence by ASA or AAS. Answer choice C uses the latter.

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2 years ago
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Vic is standing on the ground at a point directly south of the base of the CN Tower and can see the top when looking at an angle
Sindrei [870]

The angle of elevation of 61° and 72° with the height of the tower being 553.3 m. gives Vic's distance from Dan as approximately 356 meters.

<h3>How can the distance between Vic and Dan be calculated?</h3>

Location of Vic relative to the tower = South

Vic's sight angle of elevation to the top of the tower = 61°

Dan's location with respect to the tower = West

Dan's angle of elevation in order to see the top of the tower = 72°

Height of the tower = 553.3m

tan( \theta) =  \frac{opposite}{adjacent}

tan( 61 ^{ \circ}) =  \frac{553.3}{ Vic' s\: distance \: to \: tower}

distance  =  \frac{553.3}{tan ( {61}^{ \circ} )}  = 306.7

  • Vic's distance from the tower ≈ 306.7 m

Similarly, we have;

Dan's distance  =  \frac{553.3}{tan ( {72}^{ \circ} )}  = 179.8

  • Dan's distance from the tower ≈ 179.8 m

Given that Vic and Dan are at right angles relative to the tower (Vic is on the south of the tower while Dan is at the west), by Pythagorean theorem, the distance between Vic and Dan <em>d </em>is found as follows;

  • d = √(306.7² + 179.8²) ≈ 356

Therefore;

  • Vic is approximately 356 meters from Dan

Learn more about Pythagorean theorem here:

brainly.com/question/343682

#SPJ1

4 0
1 year ago
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