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Alexeev081 [22]
3 years ago
12

The mass of a proton is approximately 1.67 x 10−24, and the mass of an electron is approximately 9.11 x 10−28. Find the approxim

ate ratio of the mass of the proton to the mass of the electron.
Mathematics
2 answers:
svetoff [14.1K]3 years ago
5 0
1.67x[10^(-20)] 1.67x[10^(-24+28)]
--------------------- = -------------------------- =
9.11x[10^(-28)] 9.11

.183315(10^4)=1833.15

The proton mass is about 1833 times an electron mass

Hope this helps!
melomori [17]3 years ago
4 0

what would is be in fraction form 1/1833 or 1833/1


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He drove 178 miles in the afternoon. 248-70=178
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What is the equation of the line with an x-intercept of -1 and a y-intercept of 2? y = 2x - 2 y = - 2x 2 y = 2x 2
guajiro [1.7K]
X intercept = -1,  y = 0           (-1, 0)

<span>y intercept = 2,  x = 0           (0, 2)
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slope between (-1, 0) and (0, 2):

slope = (2 -0)/(0 - -1) =  2/1 = 2,           m = 2

Using point   (-1, 0)   x₁ = -1, y₁ = 0

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3 years ago
Maria bought g gallons of gasoline for ​$3.95 per gallon and c cans of oil for ​$4.45 per can. a. What expression can be used to
Furkat [3]

Answer:

a.) Total amount spent on gasoline and oil = $ ( 3.95g + 4.45c )

b.) Total amount spent by Maria = $ 74.02

Step-by-step explanation:

As given,

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Cost of oil per can = $ 4.45

Also given,

Maria bought g gallons of gasoline and c cans of oil

⇒ Total cost of g gallons of gasoline = g×3.95 = $3.95g

   Total cost of c cans of oil  = c×4.45 = $4.45c

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a.)

Total amount spent on gasoline and oil = $ ( 3.95g + 4.45c )

b.)

As given ,

Maria buy gasoline , g = 8.6 gallons

Maria buy cans of oil , c = 6

So,

Total amount spent = $ 3.95(8.6) + 4.45(9)

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Step-by-step explanation:

3 0
3 years ago
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Annual starting salaries for college graduates with degrees in business administration are generally expected to be between $30,
REY [17]

Answer:

a) 217

b) 1351

c) 5403

Step-by-step explanation:

Given that:

confidence interval (c) = 0.95

\alpha =1-0.95=0.05\\\frac{\alpha }{2} =\frac{0.05}{2}=0.025

The Z score of \frac{\alpha }{2} is from the z table is given as:

Z_{\frac{\alpha }{2} }=Z_{0.025}=1.96

Range = $45000 - $30000 = $15000

The standard deviation (σ) is given as:

\sigma=\frac{Range}{4} =\frac{15000}{4}=3750

Sample size (n) is given as:

 n=(\frac{Z_{\frac{\alpha}{2} }\sigma}{E} )^2

a) E = $500

n=(\frac{Z_{\frac{\alpha}{2} }\sigma}{E} )^2= (\frac{1.96*3750}{500} )^2 ≈ 217

b) n=(\frac{Z_{\frac{\alpha}{2} }\sigma}{E} )^2= (\frac{1.96*3750}{200} )^2 ≈ 1351

c) n=(\frac{Z_{\frac{\alpha}{2} }\sigma}{E} )^2= (\frac{1.96*3750}{100} )^2 ≈ 5403

7 0
3 years ago
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