All categories

2 years ago

Can someone just help me out on this please :v And I swear if I see a dam link I will report ‍♀️

Mathematics

1 answer:

Margaret [11]2 years ago

3 0

1st pic

V=πr2h

V=π6^2 ×7

V= 791.68ft

5th pic

diameter is 8 radius is half the diameter which is 4cm

V=πr2h

V=π4^2×16

V= 804.25 cm

You might be interested in

How many virtical angles are there? a)m 4 b) 8 c) 11 d) 14

lara31 [8.8K]

A) 4

∠14 & ∠12
∠11 & ∠13
∠10 & ∠8
∠7 & ∠9

vertical angles are angles directly opposite of each other and are of the same measurement.

hope this helps

5 0

3 years ago

Which row of the input/output table is incorrect?

Dahasolnce [82]

Row D because if you plug in 10 for x you get 17 not 15z

7 0

3 years ago

I'm very confused on this question and I don't know how to solve it. Any kind of help will be appreciated.

juin [17]

QP is the bisector so QPM is half NPM or

$m \angle NPM = 2 m \angle QPM$

6 0

3 years ago

Select the two values of x that are roots of this equation.

makkiz [27]

Answer:

$\implies x = (-2) \qquad or\qquad x = \dfrac{-3}{2}$

Step-by-step explanation:

Given :-

A quadratic equation is given to us.
The equation is 2x² + 7x +6=0

And we need to find out the roots of the given equation. We can use the middle term splitting method to find out the roots as ,

Given equation :-

$\implies 2x^2 + 7x +6=0$

Step 1: Find out the factors of 12 :-

We will choose the two factors such that their sum equals to the coefficient of x i.e. 7 .The factors are , 1×12 , 2×6 , 3×4 .

And 3 + 4 = 7. So we will break the middle term into 3x and 4x .

Step 2 : Breaking the middle term :-

$\implies 2x^2 + 3x+4x +6=0$

Step 3: Take out common from terms :-

$\implies x(2x + 3) +2(2x +3)=0$

$\implies ( x +2)(2x+3)=0$

Step 4 : Equate them with 0 :-

$\implies x = (-2) \qquad or\qquad x = \dfrac{-3}{2}$

Hence the correct options are C and D .

5 0

2 years ago

3/4 3√128. simplify? kindly

lisov135 [29]

Answer: 3∛2

Step-by-step explanation:

First, factor 128 .... you need three common factors to bring one on the outside of the radical.

$\dfrac{3}{4}\sqrt[3]{128} \\\\\\=\dfrac{3}{4}\sqrt[3]{4\cdot 4\cdot 4\cdot 2} \\\\\\=\dfrac{3}{4}\cdot 4\sqrt[3]{2} \\\\\\=\large\boxed{3\sqrt[3]{2} }$

6 0

3 years ago

Read 2 more answers