Question

The approximate distance between J and K is units. The approximate distance between K and L is units. The approximate distance between L and J is units. If you join all three points, then the perimeter of the triangle created is approximately units.

Answer 1

Count the distance d, which gives you 7.

Use Pythogarean theorem to find c:
${a}^{2} + {b}^{2} = {c}^{2}$
Plug in the numbers:
${4}^{2} + {3}^{2} = {c}^{2} \\ \\ = 16 + 9 \\ \\ = 25 \\ \\ c = \sqrt{25} = 5$
c is 5.

Same thing with g:
${e}^{2} + {f}^{2} = {g}^{2} \\ \\ {g}^{2} = {4}^{2} + {4}^{2} \\ \\ = 16 + 16 \\ \\ = 32 \\ \\ g = \sqrt{32} = 4 \sqrt{2} = 5.66$
g equals 5.66.