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3 years ago

Find the value if k(2,3)is a point on graph of the equation x - ky +8= 0

Mathematics

2 answers:

Allisa [31]3 years ago

5 0

Answer:

x−ky+8=0=k=x/y+8/y

k=2/3+8/3 =3.266

Step-by-step explanation:

Anettt [7]3 years ago

4 0

Answer:

k = 3.33

Step-by-step explanation:

x = 2

y = 3

x - ky + 8 = 0

2 - k(3) + 8 = 0

2 - 3k + 8 = 0

10 - 3k = 0

-3k = -10

k = 3.33

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I will mark Brainliest and I WILL REPORT LINKS!!!

Stells [14]

Answer:

y = (x-1/x+2)(x-1)

y = -3(x-1)

y = -3x+3

-3x y = 3

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x(0) y = -1

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Step-by-step explanation:

6 0

3 years ago

Use the rules of exponents to simplify the expressions. Match the expression with its equivalent value.

Lelechka [254]

Answer:

1) $\frac{(-2)^{-5}}{(-2)^{-10}}=-32$

2) $2^{-1}.2^{-4} = \frac{1}{32}$

3) $(-\frac{1}{2} )^3.(-\frac{1}{2} )^2=-\frac{1}{32}$

4) $\frac{2}{2^{-4}} = 32$

Step-by-step explanation:

1) $\frac{(-2)^{-5}}{(-2)^{-10}}$

Solving using exponent rule: $a^{-m}=\frac{1}{a^m}$

$\frac{(-2)^{-5}}{(-2)^{-10}}\\=(-2)^{-5+10}\\=(-2)^{5}\\=-32$

So, $\frac{(-2)^{-5}}{(-2)^{-10}}=-32$

2) $2^{-1}.2^{-4}$

Using the exponent rule: $a^m.a^n=a^{m+n}$

We have:

$2^{-1}.2^{-4}\\=2^{-1-4}\\=2^{-5}$

We also know that: $a^{-m}=\frac{1}{a^m}$

Using this rule:

$2^{-5}\\=\frac{1}{2^5}\\=\frac{1}{32}$

So, $2^{-1}.2^{-4} = \frac{1}{32}$

3) $(-\frac{1}{2} )^3.(-\frac{1}{2} )^2$

Solving:

$(-\frac{1}{2} )^3.(-\frac{1}{2} )^2\\=(-\frac{1}{8} ).(\frac{1}{4} )\\=-\frac{1}{32}$

So, $(-\frac{1}{2} )^3.(-\frac{1}{2} )^2=-\frac{1}{32}$

4) $\frac{2}{2^{-4}}$

We know that: $a^{-m}=\frac{1}{a^m}$

$\frac{2}{2^{-4}}\\=2\times 2^4\\=2(16)\\=32$

So, $\frac{2}{2^{-4}} = 32$

3 0

3 years ago

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Darina [25.2K]

Y = mx + b
slope(m) = 6
(-3,5)...x = -3 and y = 5
now we sub and find b, the y int
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3 years ago

Find the value if k(2,3)is a point on graph of the equation x - ky +8= 0​

Find the value if k(2,3)is a point on graph of the equation x - ky +8= 0