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3 years ago

13

Is it possible for two triangles to have the same side lengths but not be congruent?

1 answer:

Rufina [12.5K]3 years ago

7 0

When two triangles are congruent they will have exactly the same three sides and exactly the same three angles. The equal sides and angles may not be in the same position (if there is a turn or a flip), but they are there.

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Solve for y: 2x + 4y = 6

riadik2000 [5.3K]

Answer:

y equals 3/2 - 1/2 x.......

8 0

3 years ago

9/10 = z/8 round to the nearest tenth

jeka57 [31]

9/10 = z/8

cross multiply

9/10(10)(8) = z/8(8)(10)

9(8) = z(10)

72 = 10z

Isolate the z, divide 10 from both sides

72/10 = 10z/10

z = 72/10

z = 7.2

7.2, or D) is your answer

hope this helps

4 0

3 years ago

Water is pumped out of a 500-gallon tank at a rate of 2.5 gallons per second. The inequality 500−2.5t<100 can be used to dete

kherson [118]

Answer:

$160\ \text{s}$

Step-by-step explanation:

The inequality that represents the situation is

$500-2.5t$ where $t$ is the time in seconds

$\Rightarrow -2.5t$

$\Rightarrow -2.5t$

$\Rightarrow 2.5t>400$

$\Rightarrow t>\dfrac{400}{2.5}$

$\Rightarrow t>160\ \text{s}$

So, the time after which there will be less than 100 gallons of water is $160\ \text{s}$ .

7 0

3 years ago

Question is on the photo

Kaylis [27]

g=

2x+5

-----

x

g(1) g=2x+5

8 0

3 years ago

A group of children bought 3 presents that cost $W each and a card that cost $200. The children shared the total cost equally. E

Step2247 [10]

Answer:

Amount of money paid by each student is equal to $\$3W+\$200$

Step-by-step explanation:

Given: A group of children bought $3$ presents that cost $\$W$ each and a card that cost $\$200$ .

To find: amount of money each student paid in terms of $W$

Solution:

Cost of each present $=\$W$

Cost of $3$ presents $=\$3W$

Cost of a card $=\$200$

Therefore,

Amount of money paid by each student in terms of $W$ = Cost of $3$ presents + Cost of a card

$=\$3W+\$200$

4 0

3 years ago