It shall be the letter ........b
Answer:
a) 3.128
b) Yes, it is an outerlier
Step-by-step explanation:
The standardized z-score for a particular sample can be determined via the following expression:
z_i = {x_i -\bar x}/{s}
Where;
\bar x = sample means
s = sample standard deviation
Given data:
the mean shipment thickness (\bar x) = 0.2731 mm
With the standardized deviation (s) = 0.000959 mm
The standardized z-score for a certain shipment with a diameter x_i= 0.2761 mm can be determined via the following previous expression
z_i = {x_i -\bar x}/{s}
z_i = {0.2761-0.2731}/{ 0.000959}
z_i = 3.128
b)
From the standardized z-score
If [z_i < 2]; it typically implies that the data is unusual
If [z_i > 2]; it means that the data value is an outerlier
However, since our z_i > 3 (I.e it is 3.128), we conclude that it is an outerlier.
Here's an example Its also call the 'ac' method:-
factor 2x^2 - 13x - 15
Multiply first coefficient by last number which is 2*-15 = -30
Now we need 2 factors of -30 which will when added give - 13:-
-15 and 2 looks good. So we can write:-
2x^2 - 13 x - 15
= 2x^2 + 2x - 15x - 15
factor by grouping first 2 and last 2 terms , we get:-
= 2x(x + 1) - 15(x + 1)
the x+1 is common so we have:-
(2x - 15)(x + 1) Answer
Hope this helps.
Answer:
Given:
f(x) = 4x² + 1
g(x) = x² - 5
Then
(f + g)(x) = 4x² + 1 + x² - 5
= 5x² - 4
Answer: 5x² - 4
Answer:
I think that gives remind us of how pictures lokked back then and because that is what they used back then and it tells me is old
Step-by-step explanation:
