Solve for x. assuming that lines which appear tangent are tangent
1 answer:
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Answer:
5
(3a²b³c)³(2a⁴b²c²)³
= (3a⁶b⁹c³)(8a¹²b⁶c⁶)
= 24a¹⁸b¹⁵c⁹
14
⁴√(81a¹⁶b¹²c⁹)
= (⁴√81)(⁴√a¹⁶)(⁴√b¹²)(⁴√c⁹)
Answer:
5
(3a²b³c)³(2a⁴b²c²)³
= (3a⁶b⁹c³)(8a¹²b⁶c⁶)
= 24a¹⁸b¹⁵c⁹
14
⁴√(81a¹⁶b¹²c⁹)
= (⁴√81)(⁴√a¹⁶)(⁴√b¹²)(⁴√c⁹)