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kvv77 [185]
3 years ago
6

Write an equation of a line that is parallel to the line y 4x +3

Mathematics
1 answer:
maxonik [38]3 years ago
4 0

Answer:

y=4x+4

Step-by-step explanation:

There are infinite answers

All you have to do is changed the last number 3, to any real number greater or less than 3

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If f(x)=x^4+6, g(x)=x-2 and h(x)= sqrt (x), then f(g(h(x)))=
patriot [66]

Answer:

x^2 + 4x * (3 - sqrt(x)) - 2(5 + sqrt(x))

Step-by-step explanation:

Firstly let us split this up, we need to first work out what g(h(x)) is:

h(x) = Sqrt(x) so g(h(x)) = g(sqrt(x)) = sqrt(x) - 2

Now to work out f(g(h(x))) = f(sqrt(x) - 2) = (sqrt(x) - 2)^4 + 6

= (sqrt(x) - 2) * (sqrt(x) - 2) * (sqrt(x) - 2) * (sqrt(x) - 2) - 6

= (x - 2 * sqrt(x) + 4) * (x - 2 * sqrt(x) + 4) - 6

= x^2 - 2x * sqrt(x) + 4x - 2x * sqrt(x) + 4x - 8 * sqrt(x) + 4x - 8 * sqrt(x) + 16 - 6

= x^2 - 4x * sqrt(x)  + 12x - 16 * sqrt(x) + 10

= x^2 + 4x * (3 - sqrt(x)) - 2(5 + sqrt(x))

3 0
3 years ago
A customer works into a post office to purchase stamps. she purchases a total of 45 stamps. some of the stamps are 49cent stamps
baherus [9]

Step-by-step explanation:Let number of 49 cents =A

                                             Let number of 33 cents=B

<u>A+B=45    equation 1</u>

1 $=100 cents

49 cents =.49 dollar

33 cents=.33 dollar

so .<u>49A+.33B=17.89    equation 2</u>

Add equation 1 and equation 2

since these are simultaneous equations

.49A+.33B=17.89

     A+     B=45

so divide equation 2 by 100 we get

49A+33B=1789

    A+B     =45 multiply equation 1 by 33 on both the sides we get

<u>33A+33B=1485     equation 3</u>

so subtract equation 3 from equation 2 we get

49A+33B=1789  equation 2

<u>33A+33B=1485    equation 3</u>

<u>16A+0      =304</u>

16A=304

A=304/16

A=19

putting nalue of A in equation 1 we get

A+B=45

19+B=45

B=45-19

B=26

so number of 49 cent stamps are 19

and number of 33 cent stamps are 26

5 0
3 years ago
PLEASEEEEE HELPPPP MEEEEEEE BRAINLIEST TO THE FIRST ANSWER AND 30 POINTS
icang [17]

Answer:

CD ≠ EF

Step-by-step explanation:

Using the distance formula

d = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2    }

with (x₁, y₁ ) = C(- 2, 5) and (x₂, y₂ ) = D(- 1, 1)

CD = \sqrt{(-1+2)^2+(1-5)^2}

      = \sqrt{1^2+(-4)^2}

      = \sqrt{1+16} = \sqrt{17}

Repeat using (x₁, y₁ ) = E(- 4, - 3) and (x₂, y₂ ) = F(- 1, - 1)

EF = \sqrt{(- 1+4)^2+(-1+3)^2}

     = \sqrt{3^2+2^2}

     = \sqrt{9+4} = \sqrt{13}

Since \sqrt{17} ≈ \sqrt{13} , then CD and EF are not congruent

     

6 0
3 years ago
Which system of equations is represented by the graph? Picture attached
STatiana [176]
None


the slope of the suggested lines is either 1 or -1
and none of the equal to the slope of the red line in the graph wichc is 2
6 0
3 years ago
Read 2 more answers
Solve 3[-x+(2x+1)]=x-1
12345 [234]

Answer:

x = 1

Step-by-step explanation:

If you have any questions about the way I solved it, don't hesitate to ask ÷)

3 0
3 years ago
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