Answer:
2
Step-by-step explanation:
Area of a square =
(<em>s is a side length)</em>
<em>24 = </em>
=
= <em>s</em>
= <em>s</em>
<em>2</em>
= <em>s</em>
Answer:
divide the figure into two parts.
area of triangle = 1/2×base×height
area of triangle = 1/2×3×3
area pf triangle = 4.5 units²
area of square = side²
area of square = 3²
area of square = 9unit²
<h3>
Answer: -7 < x < 17</h3>
====================================================
Explanation:
Plug in the lower bound of the domain, which is x = -3
f(x) = 3x+2
f(-3) = 3(-3)+2
f(-3) = -9+2
f(-3) = -7
If x = -3, then the output is y = -7. Since f(x) is an increasing function (due to the positive slope), we know that y = -7 is the lower bound of the range.
If you plugged in x = 5, you should find that f(5) = 17 making this the upper bound of the range.
The range of f(x) is -7 < y < 17
Recall that the domain and range swap places when going from the original function f(x) to the inverse 
This swap happens because how x and y change places when determining the inverse itself. In other words, you go from y = 3x+2 to x = 3y+2. Solving for y gets us y = (x-2)/3 which is the inverse.
-----------------------
In short, we found the range of f(x) is -7 < y < 17.
That means the domain of the inverse is -7 < x < 17 since the domain and range swap roles when going from original to inverse.

Put it back into the equation,

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Answer:
the height after 2 seconds will be 128 feet
Step-by-step explanation:
Data provided in the question:
Initial velocity = 96 feet per second
The function of height of falling debris above the ground is given as:
h(t) = 96t - 16t²
A) To find height after time t = 2 seconds
substituting the value of time in the above function, we get
h(t) = 96 × 2 - 16 × 2²
or
h(t) = 192 - 16 × 4
or
h(t) = 192 - 64
or
h(t) = 128 feet
Hence,
the height after 2 seconds will be 128 feet