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never [62]
2 years ago
7

Help me plzzzzzzzzzzzz

Mathematics
1 answer:
Ad libitum [116K]2 years ago
3 0

Looking at the triangle we see the angles:

58, x

We also see a right angle, therefore you now have:

90, 58, 0

All three angles of a triangle should have a total of 180 degrees, so we add the known angles and subtract the total from 180.

90 + 58 = 148

180 - 148 = 32

Therefore, x = 32 or C

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What is the lcm of 4 and 5
timama [110]

Answer:

20

Step-by-step explanation:

4 * 1 = 4        5 * 1 = 5

4 * 2 = 8        5 * 2 = 10

4* 3 = 12        5 * 3 = 15

4 * 4 = 16       5 * 4 = 20

4 * 5 = 20


they both go into 20 equally. there is no number lower than 20 that they both go into

8 0
2 years ago
Graph -2x+10+5y=0 using intercepts. Add two intercept points on the graph.
mihalych1998 [28]
If you need any steps explained lmk

7 0
2 years ago
Cos s=-2/5 and sin t=4/5, s and t are in quadrant II<br> find cos(s+t) and cos(s-t)
mojhsa [17]

Answer:

•cos(s+t) = cos(s)cos(t) - sin(s)sin(t) = (-⅖).(-⅗) - (√21 /5).(⅘) = +6/25 - 4√21 /25 = (6-4√21)/25

•cos(s-t) = cos(s)cos(t) + sin(s)sin(t) = (-⅖).(-⅗) + (√21 /5).(⅘) = +6/25 + 4√21 /25 = (6+4√21)/25

cos(t) = ±√(1 - sin²(t)) → -√(1 - sin²(t)) = -√(1 - (⅘)²) = -⅗

sin(s) = ±√(1 - cos²(s)) → +√(1- cos²(s)) = +√(1 - (-⅖)²) = √21 /5

5 0
2 years ago
How many like terms are in the expression:5a^2+6b+a^2-3b-2+4c.
Goryan [66]

Solution

Part 3

For this case we have 6 different terms

Part 4

We can do the following:

5a^2+a^2+6b-3b+4c-2

Part 5

And we can simplify on this way:

6a^2+3b+4c-2

7 0
1 year ago
(If A(2, -3), B(3,-2) and point C divides the line segment AB in the ratio of 1: 2, find OC.)​
Anna007 [38]

Answer:

A(2, -3) and B(3, -2), o(0, 0) Let C(x, y)

Here c divide AB line in the ratio of 1:2

From the line intersection law, we get x=(m1×x2+m2×x1)/(m1+m2)

and y=(m1×y2+m2×y1)/(m1+m2)

where m1=1, m2=2, x1=2, x2=3, y1=-3, y2=-2;

so x=(3+4)/3

  or, x=7/3;

y=(-2-6)/3

 or, y=-8/3;

so, oc=√((0-7/3)²+(0-(-8/3))²)

oc=3.54

7 0
1 year ago
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