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Orlov [11]
3 years ago
11

3x(-2x)8(-2)=30 what value of x makes the equation true. A. 24 B.26 C.5 D.6

Mathematics
1 answer:
Leokris [45]3 years ago
5 0

Answer:

Step-by-step explanation:

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A number was multiplied by 6 then increased by 3 and the result was 33
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The number that you are trying to find is 5
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3 years ago
Prove the polynomial identity.
aleksandr82 [10.1K]

Explanation:

Since we have given that

(2x+1)^2-2(2x+1)

Now, we have to prove it as

(2x+1)(2x-1)

Now, start the iterations:

(2x+1)^2-2(2x+1)\\\\=4x^2+1+4x-4x-2\\\\=4x^2+1-2\\\\=4x^2-1\\\\=(2x)^2-1\\\\=(2x+1)(2x-1)

So, first blank will be filled with

4x^2+4x+1

Second blank will be filled with

4x^2-1

Hence proved.

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3 years ago
You have 10 boxes and you shade 3 of the boxes what is the fraction of that.
7nadin3 [17]
If you have 10 boxes and you shade 3 of these boxes, then the fraction of shaded boxes is 3/10.  The fraction of unshaded boxes would just be the remainder of boxes, or 7/10.
7 0
2 years ago
The following statistics represent weekly salaries at the Midtown Construction Company.
Sphinxa [80]

Answer:

5

Step-by-step explanation:

4 0
3 years ago
PLEASE HELP!
wariber [46]

Answer: The maximum value: P = 6x + 7y - 2 is 84 at (5,8).

Step-by-step explanation:

Here, Object of constraint P(max) = 6x + 7y - 2.

And, the system of constraints,

x≤5,   y≤(1/5)x + 7,   x≥0,   y≥0        

Since, x= 5 is a line parallel to y-axis.

And  at origin it is giving 0≤5 ( false)

Thus the area of inequality x≤5 does not contain the origin.

Now, x -intercept and y-intercept of line y=(1/5)x + 7 are (-35,0) and (0, 7) respectively.

Also, at (0, 0),  0 ≤(1/5)×0 + 7 (true)

Therefore, inequality y≤(1/5)x + 7 will contain the origin.

Now, x≥0,   y≥0  shows the first quadrant.

Thus, we get feasible region ABCD.

In which at A≡(0,7), P = 49.

At B≡(5,8), P= 84,

At C≡(5,0), P= 30,

And, D≡(0,0), P= 0

Therefore at B, P is maximum.

8 0
3 years ago
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