Answer:One can do a two-proportion test and find that the z-value for different is 1.28 (or -1.28, depending how one sets up the test).
The p-value for that is 0.20, so by most tests this is not statistically significant.
Said another way, if there had been no change in the interval, the probability of having a repeat sample at least this different would be 0.20.
The parameter one is attempting to determine is the true proportion of adults in the US who say they like pizza.
For those who think it is 50%, it is essentially 100% likely that it is not 50% but much higher, around 75-77%.
89 divided by 6 = 14.83… the … are 3's but they go on forever, so you round to the hundredths and the 3 doesn't bump the 3 up so the answer is 14.83
Answer:
correct answers bc and d just did it
Step-by-step explanation:
It’s going to be 99 but I’m not sure
