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2 years ago

Say a joke for Brainslet have fun!

Mathematics

2 answers:

dsp732 years ago

8 0

Answer:

How do you teach a chicken math?

Step-by-step explanation:

Show it lots of egg-samples

give brainliest? ;)

ladessa [460]2 years ago

3 0

Hellooooo!!!!

My joke is, what has a neck but no head, but can wear a cap?

Have fun! please give brainliest if you could!! <3

You might be interested in

|y+4|<1 Solve and Show your work?

kobusy [5.1K]

$\sqrt{815}$

6 0

3 years ago

If P and Q are two sets then n( P-Q) means ?

Lapatulllka [165]

$\huge{\mathbb{ \tt{ANSWER}}}$

I shall use the symbol U for union

^ for intersection

~ for complement

The property of set subtraction states that for any sets X and Y, X-Y = X ^ Y~

That is in words, X throw away Y is the same as the intersection of X and the complement of Y

or X and anything NOT in Y

At the SET level, the proof looks like this:

(P-Q) U (Q-P) = « given

(P^Q~) U (Q ^ P~) = « property of set subtraction

(P U Q) ^ (P U P~) ^ (Q~ U Q) ^ (Q~ U P~) = « distributive property

(P u Q) ^ (Q~ U P~) = « Union of any set with it's complement is the universal

set which gets dropped by any intersection of a non-universal set

(P u Q ) ^ (Q ^ P)~ = « De Morgan's Law

(P u Q) - (Q ^ P) = « property of set subtraction

(P u Q) - (P ^ Q) « commutative property

At the ELEMENT level, the proof looks like this:

» Proves left side is subset of right side

If x is in (P-Q) U (Q-P) then x is in (P-Q) OR x is in (Q-P)

If x is in P-Q then x is in P but not in Q.

Then X is in P U Q.

Since x is not in Q, x is NOT in P ^ Q

Hence x is in P U Q but NOT in P^Q, which

means it is an element if (P U Q) - (P ^ Q)

Therefore x is an element of the set defined by the right side, which means (P-Q) U (Q-P) is a subset of (P U Q) - (P ^ Q)

« proves right side is subset of the left side

If x is an element of (P U Q) - (P ^ Q) then

x is in (P U Q) but NOT in (P^Q)

Since x is in P U Q, x is in P OR x is in Q.

Since x is NOT in (P^Q) then x is NOT in BOTH P and Q.

Hence x is in either P or Q but not both.

If x is in P, then x is not in Q, so x is in P-Q.

Therefore x is in (P-Q) U (Q-P).if x is in Q, then x is not in P, so x is in Q-P.Therefore x is in (Q-P) U (P-Q).There x is an element of set defined by the left side, which menas (P u Q)-(P ^Q) is a subset of (P-Q) U (Q-P).

#CarryOnLearning

#LetsEnjoyTheSummer

8 0

3 years ago

The ratios of corresponding sides in the two triangles

Ratling [72]

Answer:

2nd Choice

Step-by-step explanation:

because in SAS, we use 2 sides and the angle between them

5 0

3 years ago

Help I will be marking brainliest!!!! A. 55.33 B. 156.16 C. 72 D. 61.16

Ksju [112]

Answer:

do RN/RM first which will be 95/73 which is 1.30 and use this to multiply 47 which is 47*1.3 61.1

ANSWER = D.

I first got the variable of 1.3 which is multiply that by RM to get RN and then useing that logic you multiply 1.3 by MP to get QN

MARK ME BRAINLIEST

6 0

3 years ago

Please help i need the answer

deff fn [24]

Tv
Kid that
Motor big boom
GfbLmkfh. !. Fhng fnh fny nt

3 0

3 years ago