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algol13
3 years ago
7

Please answer this question

Mathematics
1 answer:
Virty [35]3 years ago
6 0

Answer:

1. 38 = 1 • 38

2. 38 = 2 • 19

Step-by-step explanation:

2. 38 ÷ 19 = 2

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Find a solution of the linear inequality. y ≥ 4x – 5
Harlamova29_29 [7]
I think its (1,1)please  correct me if i am wrong. have a good day!! :)
7 0
4 years ago
Read 2 more answers
Factor the expression. Use the fundamental identities to simplify, if necessary.
Rasek [7]

Answer:

see explanation

Step-by-step explanation:

Using the trigonometric identity

sin²x + cos²x = 1 ⇒ sin²x = 1 - cos²x

Given

sin²x + 7cosx + 17

=1 - cos²x + 7cosx + 17

= - cos²x + 7cosx + 18 ← factor out - 1 from each term

= - (cos²x - 7cosx - 18)

Consider the factors of the constant term (- 18) which sum to give the coefficient of the cosx term (- 7)

The factors are - 9 and + 2, thus

= - (cosx - 9)(cosx + 2) ← in factored form

3 0
3 years ago
PLEASE HELP!!!!!!!!!<br> Solve the equation showing all work. <br> 7 + 14 = −21
scZoUnD [109]
False -The equality is false because one side is positive and other is negative
3 0
3 years ago
Which situation can be represented by 80x &gt; 150 + 50x?
V125BC [204]

Answer:

All numbers greater than 5, i.e., x>5 .

Step-by-step explanation:

The given inequality is  

80x>150+50x

Isolate variable terms on one side to find the solution.

Subtract  50x from both sides.

80x-50x>150+50x-50x

30x>150

Divide both sides by 30.

\dfrac{30x}{30}>\dfrac{150}{30}

x>5

It means, all the numbers which are greater than 5, are the solutions of the given inequality and 5 is not included in the solution set.

6 0
3 years ago
Triangle A"B"C" is formed using the translation (x + 2 y + 0) and the dilation by a scale factor of from the origin. Which equat
kramer

Answer:

segment a double prime b double prime = segment ab over 2

Step-by-step explanation:

Triangle A″B″C″ is formed using the translation (x + 2, y + 0) and the dilation by a scale factor of one half from the origin. which equation explains the relationship between segment ab and segment a double prime b double prime?

coordinate plane with triangle ABC at A (- 3,  3), B (1, - 3), and C (- 3, -3).

segment a double prime b double prime = segment ab over 2

segment ab = segment a double prime b double prime over 2

segment ab over segment a double prime b double prime = one half

segment a double prime b double prime over segment ab = 2

Answer:  If triangle ABC at A (- 3,  3), B (1, - 3), and c (- 3, -3) is translated using   (x + 2, y + 0), then the new coordinates of triangle ABC would be at A'(- 3 + 2,  3), B'(1 + 2, - 3), and C'(- 3 + 2, -3) Which is A'(- 1,  3), B'(3, - 3), and C'(- 1, -3). The dilation by a scale factor of from the origin gives A″ (-1/2, 3/2), B″ (3/2, -3/2) and C″(-1/2, -3/2) = (-0.5, 1.5), B″ (1.5, -1.5) and C″(-0.5, -1.5)

The distance AB and A"B" are given as:

AB=\sqrt{(1-(-3))^2+(-3-3)^2} =\sqrt{5 2} \\\\A"B"=\sqrt{(1.5-(-0.5))^2+(-1.5-1.5)^2} =\sqrt{13}

AB = √52 = √(4×52) = 2√13 = 2A"B"

A"B" = AB/2

3 0
3 years ago
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