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Amanda [17]
3 years ago
11

What is the midpoint and distance between points P(3,5) and Q(7,5)

Mathematics
1 answer:
storchak [24]3 years ago
4 0

The formula of a midpoint:

M\left(\dfrac{x_1+x_2}{2};\ \dfrac{y_1+y_2}{2}\right)

The formula of a distance between two points:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

We have the points P(3, 5) and Q(7, 5). Substitute:

x=\dfrac{3+7}{2}=\dfrac{10}{2}=5\\\\y=\dfrac{5+5}{2}=\dfrac{10}{2}=5

<h3>M(5, 5)</h3>

d=\sqrt{(5-5)^2+(7-3)^2}=\sqrt{0^2+4^2}=\sqrt{4^2}=4

<h3>Answer:</h3><h3>Midpoint = (5, 5)</h3><h3>Distance = 4</h3>
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Step-by-step explanation:

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Let event A = alarm gets triggered

Probability that alarm gets trigger given the bags contain forbidden material, P(A/F) = 0.77

Probability that alarm gets trigger given the bags does not contain forbidden material, P(A/NF) = 0.20

(1) Probability that a bag triggers the alarm, P(A) ;

         P(A) = P(F) * P(A/F) + P(NF) * P(A/NF)

                 = (0.69 * 0.77) + (0.31 * 0.20) = 0.5313 + 0.062

                 = 0.5933

Therefore, probability that a bag triggers the alarm is 0.5933 .

(2) Probability that a bag that triggers the alarm will actually contain forbidden material is given by P(F/A) ;

Using Bayes' Theorem;

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3 years ago
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Answer:

the piont was 10.15 away from the that is dead see yea

Step-by-step explanation:

5 0
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