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skad [1K]
3 years ago
11

URGENT NEED IMMEDIATE SUPPORT WILLING TO GIVE BRAINLY

Mathematics
1 answer:
frozen [14]3 years ago
8 0

4 hours for 18

7 hours for 25.50

Difference in hours: 7-4 = 3

Difference in cost: 25.50 - 18 = 7.50

7.50 / 3 = 2.50

A. They charge 2.50 per hour.

B. 2.50 x 4 = 10

18 - 10 = 8

The flat fee is 8 dollars

C. 8 + (2 x 2.50) = 13 dollars

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if the question is write an equation to find the total cost of a night of bowling then the answer is

y=16x

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Step-by-step explanation:

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Describe all of the symmetries for the following figure.
Free_Kalibri [48]

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On the last day of school, Mrs. Awesome gave jelly beans to her class. She gave each boy as many jelly beans as there were boys
professor190 [17]

Answer:

28 students

Step-by-step explanation:

Let x be the number of girls in the class. There were two more boys than girls in her class, then the number of boys is x + 2.

Mrs. Awesome gave each boy as many jelly beans as there were boys in the class, so each of x + 2 boys got x + 2 jelly beans, so

Number of boys = x + 2

Number of jelly beans each boy got = x + 2

Total number of jelly beans all boys got = (x + 2)(x + 2)

Mrs. Awesome gave each girl as many jelly beans as there were girls in the class, so each of x girls got x jelly beans, so

Number of girls = x

Number of jelly beans each girl got = x

Total number of jelly beans all girls got = (x)(x)

Hence,

Total number of jelly beans class got = (x + 2)(x + 2) + (x)(x)

Mrs. Awesome brought 400 jelly beans, and when she finished, she had six jelly beans left, so she gave 400 - 6 = 394 jelly beans to the calss.

So,

(x+2)(x+2)+(x)(x)=394\\ \\x^2+2x+2x+4+x^2=394\\ \\2x^2+4x+4-394=0\\ \\2x^2+4x-390=0\\ \\x^2+2x-195=0\\ \\D=2^2-4\cdot (-195)=4+780=784\\ \\\sqrt{D}=28\\ \\x_{1,2}=\dfrac{-2\pm 28}{2\cdot 1}=-15,\ 13

Number of girls cannot be negative, so x = 13, x + 2 = 15 and total number of students is 13 + 15 = 28

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3 years ago
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Step-by-step explanation:

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3 years ago
PLEASE HELP WILL GIVE BRAINLIEST!!!!
finlep [7]

Answer:

Make a graph

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