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1 year ago

I need the Answer Immediately!!!!

Mathematics

1 answer:

Reika [66]1 year ago

5 0

Answer:

y = -5x -8

Step-by-step explanation:

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Question: When you do adding fractions, do you have to find a common demoniter? *sorry for misspelling*

docker41 [41]

Answer: yes when your adding or subtracting fractions you must find the common denominator between the two before you continue.

Step-by-step explanation:

Example: 2/4+3/2

Find the common denominator. ( in this case the common denominator is 4)

We keep the first fraction as it is cause it has the denominator 4 and we multiply the second fraction by 2 up and down to get a denominator of 4. The equation becomes 2/4+6/4

Now you add the numerators and you got your answer ( don’t forget to simplify)

The answer after adding in this case is 8/4 and when simplified it is 2

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2 years ago

Which function is graphed on the coordinate plane below?

Law Incorporation [45]

F(x)= 2x-6

Y=Mx+b

B= y intercept= -6

M= how many times it went up so 2 times

Hope this helped :))

6 0

2 years ago

a deli employee can make a sandwhich in 6 minutes.she works for 84 minutes.how many sandwhiches can she make

Leni [432]

Answer:

Step-by-step explanation:

84/6

6 0

2 years ago

Read 2 more answers

Graph g(x) = -3(x + 2)2 + 2. Compare the graph to the graph of f(x) = x2. Give me five points that you use to graph g(x). Then d

PolarNik [594]

The answer would be -20 because you add and subtract your numbers to get 20

4 0

2 years ago

One positive number is 14 less than another positive number. If the reciprocal of the smaller number is added to five times the

Kipish [7]

Let's call the two numbers $s$ and $l$ .

Given these variables, we can say: $s = l - 14$ , based on the first sentence in the problem.

Also, remember that the reciprocal of a number is simply 1 divided by the number. Thus, we can say that:

$\dfrac{1}{s} + 5\Big( \dfrac{1}{l} \Big) = \dfrac{1}{4}$

To solve, we can simply substitute $l -14$ in for $s$ in the second equation and solve.

$\dfrac{1}{l - 14} + \dfrac{5}{l} = \dfrac{1}{4}$

Set up

$\dfrac{l}{l(l - 14)} + \dfrac{5(l - 14)}{l(l - 14)} = \dfrac{1}{4}$

Get terms on the left side to a common denominator for easier addition

$\dfrac{l + 5l - 70}{l(l - 14)} = \dfrac{1}{4}$

Simplify

$4(6l - 70) = l(l - 14)$

Cross multiplication ( $\frac{a}{b} = \frac{c}{d} \Rightarrow ad = bc$ )

$24l - 280 = l^2 - 14l$

Simplify

$l^2 - 38l + 280 = 0$

Subtract $24l - 280$ from both sides of the equation

$(l - 10)(l - 28) = 0$

Factor left side of the equation

$l = 10, 28$

Zero Product Property

Now, notice that we have found two solutions, but the problem is only asking for one. This <em>likely </em>means that one of our solutions is extraneous. Let's take a look. Remember that the smaller positive number is equal to 14 less than the larger number. However,

$s = 10 - 14 = -4$ ,

Since $s$ is not positive in this case, $l = 10$ is not a solution.

Thus, $l = 28$ is our only solution. In this case,

$s = 28 - 14 = 14$ ,

which means that the smaller number is 14 and the larger number is 28.

5 0

2 years ago