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aalyn [17]
3 years ago
15

F(x) = 2x+6, g(x) = 3² findf(g (-3))​

Mathematics
2 answers:
weeeeeb [17]3 years ago
6 0

Step-by-step explanation:

If F(x) = 2x+6, g(x) = 3² findf(g (-3))

Solution

f(g (-3)) = 2x+6(3²(-3)) = 2x+6(3×3(-3))

= 2x+6(-27) = 54x-162 = 54x = 162

54/54x = 162/54

x = 3

Yanka [14]3 years ago
5 0

Answer:

➩ f(g(-3)) = 24

Step-by-step explanation:

➨ Rearrange/Simplify the equations

F(x)=2x+6\\g(x)=9

➨ Find f(g(-3))

g(-3)=9 ➩ All x-values have same y-values ➩ Constant Function

Substitute g(-3) = 9 in the f(x)

f(g(-3)) = f(9)\\f(9)=2(9)+6\\f(9)=18+6\\f(9)=24\\f(g(-3)) = 24

Thus, the answer ➩ f(g(-3)) = 24

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Rewrite in simplest rational exponent form <img src="https://tex.z-dn.net/?f=%5Csqrt%7Bx%7D%20%2A%20%5Csqrt%5B4%5D%7Bx%7D" id="T
Shkiper50 [21]

The given expression written in the simplest rational exponent form is x^{\frac{3}{4} }

<h3>Writing an Expression in Exponent form</h3>

From the question, we are to write the given expression in exponent form

The given expression is

\sqrt{x}  \times \sqrt[4]{x}

In exponent form,

\sqrt{x}  = x^{\frac{1}{2} }

and

\sqrt[4]{x} = x^{\frac{1}{4} }

Thus,  \sqrt{x}  \times \sqrt[4]{x} becomes

x^{\frac{1}{2} } \times x^{\frac{1}{4} }

Applying the multiplication law of indices, we get

x^{\frac{1}{2} + \frac{1}{4} }

= x^{\frac{3}{4} }

Hence, the given expression written in the simplest rational exponent form is x^{\frac{3}{4} }

Learn more on Writing an expression in exponent form here: brainly.com/question/4421494

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