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3 years ago

4/3C, when C=6 show your work here

Mathematics

2 answers:

jok3333 [9.3K]3 years ago

8 0

Answer: 2/9

Work: So, you are going to get the equation after plugging in the number 4/3(6), after simplifying even more, you get 4/18. Then you simplify again and divide both sides (Numerator and denominator) and you get 2/9.

<em>I hope this helps, and Happy Holidays! :)</em>

tresset_1 [31]3 years ago

6 0

4 divided by 3C

If C equals 6, then the equation now looks like 4 divided by 3(6).

3 x 6 = 18.

4 divided by 18 is .22 repeating.

This may be wrong. Check with another answer.

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How do I find the x and the y

mart [117]

Answer:

x = 22

y = 35

Step-by-step explanation:

Because its an isosceles triangle, you know the base angles are equal so:

$3x - 11 = 2x + 11$

Solving:

subtract 2x from both sides

$x-11=11$

add 11 to both sides

$x = 22$

Next, find the angle measures of the two base angles:

$3*22-11\\66-11\\55$

To find y, you know that the interior angles of the whole triangle add up to 180, so you have

$55 + 55 + 2y = 180$

solving,

$110 + 2y = 180$

subtract 110 from both sides

$2y = 70$

divide both sides by 2

$y = 35$

3 0

2 years ago

Read 2 more answers

Which number(s) below belong to the solution set of the equation? Check all that apply.x + 12 = 13A.14B.1C.13D.312E.0F.25

Darya [45]

X + 12 = 13
x = 13 - 12
x = 1

The only solution is x = 1
letter B

4 0

3 years ago

A light bulb in Maya's house uses 9.4 watts of electric power each minute it is on. If the light bulb used a total of 6.58 watts

tamaranim1 [39]

Answer:

0.7 minute

Step-by-step explanation:

Given that each (1) minute a light use 9.4 watts.

So If the light bulb used a total of 6.58 watts, the minutes was on it is:

$\frac{The total watts used}{The watts used each minute}$

= $\frac{6.58}{9.4}$

= 0.7 minute

So the the minutes was on it is 0.7

Hope it will find you well!

4 0

3 years ago

Is my answer correct?

Alexandra [31]

Yes your answer would be correct! :)

8 0

3 years ago

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Which gives the prices in order, from least to greatest

k0ka [10]

Answer:

is there a picture to go with the problem?

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3 years ago