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3 years ago

A math test has 12 multiplication problems and 24 division problems.

Mathematics

2 answers:

dimaraw [331]3 years ago

6 0

Answer: 2:1

Step-by-step explanation:

hi there! since there are 24 division problems and 12 division problems, you need to divide by the gcf of 24 and 12, which gives you 2:1.

hope it helps!

lovelymoonlight

Kay [80]3 years ago

4 0

Answer: 2:1 is the ratio of division problems to multiplication problems.

Step-by-step explanation:

12 is half as small as 24, so the ratio of division problems to multiplication problems is 2:1.

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IgorLugansk [536]

Answer: 180/540
Simplified term would be 1/3
The answer is b

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Scilla [17]

Answer:

Step-by-step explanation:

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<img src="https://tex.z-dn.net/?f=%5Cfrac%7B%5Csec%5Cleft%28x%5Cright%29%7D%7B%5Ccos%5Cleft%28x%5Cright%29%7D-%5Cfrac%7B%5Csin%5

DanielleElmas [232]

Answer:

Step-by-step explanation:

First, convert all the secants and cosecants to cosine and sine, respectively. Recall that $csc(x)=1/sin(x)$ and $sec(x)=1/cos(x)$ .

Thus:

$\frac{sec(x)}{cos(x)} -\frac{sin(x)}{csc(x)cos^2(x)}$

$=\frac{\frac{1}{cos(x)} }{cos(x)} -\frac{sin(x)}{\frac{1}{sin(x)}cos^2(x) }$

Let's do the first part first: (Recall how to divide fractions)

$\frac{\frac{1}{cos(x)} }{cos(x)}=\frac{1}{cos(x)} \cdot \frac{1}{cos(x)}=\frac{1}{cos^2(x)}$

For the second term:

$\frac{sin(x)}{\frac{cos^2(x)}{sin(x)} } =\frac{sin(x)}{1} \cdot\frac{sin(x)}{cos^2(x)}=\frac{sin^2(x)}{cos^2(x)}$

So, all together: (same denominator; combine terms)

$\frac{1}{cos^2(x)}-\frac{sin^2(x)}{cos^2(x)}=\frac{1-sin^2(x)}{cos^2(x)}$

Note the numerator; it can be derived from the Pythagorean Identity:

$sin^2(x)+cos^2(x)=1; cos^2(x)=1-sin^2(x)$

Thus, we can substitute the numerator:

$\frac{1-sin^2(x)}{cos^2(x)}=\frac{cos^2(x)}{cos^2(x)}=1$

Everything simplifies to 1.

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3 years ago

84 ÷ (17 × 3 - 23) × 4

Zielflug [23.3K]

Answer: 12

Step-by-step explanation:

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3 years ago

Determine whether the function f(x)= 1/x^2 is even, odd or neither.

gulaghasi [49]

The function f(x)= 1/x^2 is even. Hope that helps!

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