3 years ago

Find the missing side. Need help please. Need to know how to get the answer.

Mathematics

1 answer:

Lelu [443]3 years ago

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Do 59x13 divide by 2

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What is the first term, common difference, and 16th term

strojnjashka [21]

Answer:

The 1st term is -67

Step-by-step explanation:

I. When Sn = $\frac{n}{2}$ ( $a_{1} + a_{n}$ )

If Sn = 124, n = 8 and $a_{n}$ = 98

124 = 8/2(a + 98)

124 = 4(a + 98)

124 = 4a + 392

124 - 392 = 4a

-268/4 = a

-67 = $a_{1}$

Hope that help :D

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3 years ago

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san4es73 [151]

Answer:

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Step-by-step explanation:

120521x=0

x=0/120521=0

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3 years ago

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Delvig [45]

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3 years ago

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snow_tiger [21]

The answer to the question is d.

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3 years ago

The number of bacteria in a refrigerated food product is given by N ( T ) = 22 T 2 − 123 T + 40 , 6 < T < 36 , where T is

antoniya [11.8K]

Answer:

$N(T(t)) = 1408t^2 - 385.6t - 105.52$

Time for bacteria count reaching 8019: t = 2.543 hours

Step-by-step explanation:

To find the composite function N(T(t)), we just need to use the value of T(t) for each T in the function N(T). So we have that:

$N(T(t)) = 22 * (8t + 1.7)^2 - 123 * (8t + 1.7) + 40$

$N(T(t)) = 22 * (64t^2 + 27.2t + 2.89) - 984t - 209.1 + 40$

$N(T(t)) = 1408t^2 + 598.4t + 63.58 - 984t - 169.1$

$N(T(t)) = 1408t^2 - 385.6t - 105.52$

Now, to find the time when the bacteria count reaches 8019, we just need to use N(T(t)) = 8019 and then find the value of t:

$8019 = 1408t^2 - 385.6t - 105.52$

$1408t^2 - 385.6t - 8124.52 = 0$

Solving this quadratic equation, we have that t = 2.543 hours, so that is the time needed to the bacteria count reaching 8019.

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4 years ago