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guapka [62]
2 years ago
12

Solve for x. x2 + 4x - 21 = 0

Mathematics
1 answer:
Anton [14]2 years ago
4 0
2x + 4x - 21 = 0
6x - 21 = 0
6x = 21
x=3.5
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10 of 10
Fed [463]

Let the height of the rectangle = h

2b + 2h = 100

2(38) + 2h = 100

2h = 100 - 76

h = 12mm

area of rectangle = base x height

= 38 x 12

= 456mm²

4 0
2 years ago
Read 2 more answers
Evaluate the expression: (–2)2 + (–42) + (18 – 23).
marta [7]

Answer:

-51 (no options are matching)

Step-by-step explanation:

Given: (–2)2 + (–42) + (18 – 23).

we know, 2*2 = 4, and in integer multiplication if any negative integer is multiplied with positive integer, then the result will have a negative sign.

= -4 + (-42) + (18 – 23)

Here, we have open the brackets, and written the respective signs with the integers,

= - 4 - 42 - 5

now, we will perform the integer addition. Adding all the positives together & he negative numbers together

= -51

PS: It happens to be that none of the given options match with the correct answer. But, i have solved taking the expression, i hope it helps

6 0
3 years ago
Read 2 more answers
Gabriela has dinner at a cafe and the cost of her meal is \$45.00$45.00dollar sign, 45, point, 00. Because of the service, she w
Olegator [25]
The total bill amount before the service fee is given as $45.
We are given that the tip she wants to leave is 15% of the bill amount, this means that:
tip value = 0.15 * 45 = 6.75$

The total bill would be the summation of the original bill and the tip value she left.

Total bill amount = 45 + 6.75 = 51.75$
6 0
3 years ago
Read 2 more answers
Write the first four terms of the sequence:<br> a = 2<br> an = a(n-1) + 4
eduard

We have sequence equation a_n=a(n-1)+4.

In this case n is a natural number (1, 2, 3, ...).

So start inserting and computing value of a_n given that you know the value of n and a.

a_1=2(1-1)+4=4 (first term)

a_2=2(2-1)+4=6 \\a_3=2(3-1)+4=8 \\a_4=2(4-1)+4=10

Hope this helps.

3 0
2 years ago
I’ll give brainliest!
iren [92.7K]

Answer:

okay ans is A(w)=w2+5w-1/8piw2

6 0
2 years ago
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