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Yanka [14]
3 years ago
7

What are the square roots of 362

Mathematics
1 answer:
stich3 [128]3 years ago
5 0
19.0 is the only square root 362 can have
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natima [27]

Answer:

I think the answer is 432 cubic inches( in^3). Answer is the first option.

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Thank you for helping me
dedylja [7]

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Step-by-step explanation:

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I report if you answer randomly.
sasho [114]

Answer:

C. n=23; p^=0.5

Step-by-step explanation:

Normal distribution is symmetrical about the mean.

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3 years ago
An engineer has designed a valve that will regulate water pressure on an automobile engine. The valve was tested on 280 engines
DENIUS [597]

Answer:

The value of the test statistic is t = -2.09

Step-by-step explanation:

The null hypothesis is:

H_{0} = 6.6

The alternate hypotesis is:

H_{1} \neq 6.6

Our test statistic is:

t = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation(square roof of the variance) and n is the size of the sample.

In this problem, we have that:

X = 6.5, \mu = 6.6, \sigma = \sqrt{0.64} = 0.8, n = 280

So

t = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

t = \frac{6.5 - 6.6}{\frac{0.8}{\sqrt{280}}}

t = -2.09

The value of the test statistic is t = -2.09

4 0
3 years ago
In ΔQRS, the measure of ∠S=90°, the measure of ∠Q=83°, and RS = 7 feet. Find the length of SQ to the nearest tenth of a foot.
Simora [160]

Answer:

x ~0.9

Step-by-step explanation:

To solve for (x) in the given right triangle, use the trigonometric ratios, which are the following,

sin(\theta)=\frac{opposite}{hypotenuse}\\\\cos(\theta)=\frac{adjacent}{hypotenuse}\\\\tan(\theta)=\frac{opposite}{adjacent}

Each of the sides of a triangle is named with respect to the given angle. In this problem, one is given the side opposite to the given angle, and the side adjacent to it. Use the ratio of tangent (tan) to solve for the unknown side.

tan(83)=\frac{7}{x}

Manipulate the equation so that it is solved for (x),

x=\frac{7}{tan(83)}

x ~ 0.859

3 0
3 years ago
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