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3 years ago

PLEASE HELP MEEEEE <3

Mathematics

1 answer:

Svetradugi [14.3K]3 years ago

8 0

Answer:

The second choice is correct.

Step-by-step explanation:

The softball cannot be anything under 180 grams because that would go past the ten gram limit. As well as the ball cannot go any higher than 200 grams.

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N=8 x=5 p=9 np+5(x+1) - px =

cluponka [151]

Answer:

Step-by-step explanation:

3 0

3 years ago

-n+(-4)-(-4n)+6<br><br><br> solve

tigry1 [53]

Answer:

3n + 2

Step-by-step explanation:

-n+(-4)-(-4n)+6

= -n -4 +4n +6 [positive plus negative = negative; ∴ +(-4) = -4

=4n - n +6 - 4 negative plus negative = positive; ∴ -(-4n) = 4]

now subtract n from 4n and subtract 4 from 6

=3n + 2

8 0

3 years ago

Read 2 more answers

How do you solve 8/11(n-10)=64

krek1111 [17]

Answer:

n = 98

Step-by-step explanation:

8/11 x (n - 10) = 64

multiply both sides of the equation by 11/8

11/8 x 8/11 x (n-10) = 11/8 x 64

reduce the numbers with greatest common divisor 11

1/8 x 8 (n-10) = 11/8 x 64

n - 10 = 11 x 8

multiply the numbers

n - 10 = 88

so then you add the numbers

n = 88 + 10

n= 98

6 0

3 years ago

Can someone help me out with this plzzz

Furkat [3]

I am not sure ...but I tried solving it

7 0

3 years ago

What is the height of an equilateral triangle if the sides are 10

4vir4ik [10]

Answer:

The height of the equilateral triangle is $5\sqrt{3}\ units$

Step-by-step explanation:

we know that

An equilateral triangle has three congruent sides, and three congruent angles that each measure 60 degrees

To find out the height of an equilateral triangle, apply the Pythagoras Theorem in the right triangle ABD

Remember that the height of an equilateral triangle bisects the base.

see the attached figure to better understand the problem

$AB^2=AD^2+BD^2$

substitute the given values

$10^2=5^2+BD^2$

Solve for BD

$100=25+BD^2$

$BD^2=100-25$

$BD^2=75$

$BD=\sqrt{75}\ units$

simplify

$BD=5\sqrt{3}\ units$ `

therefore

The height of the equilateral triangle is $5\sqrt{3}\ units$

7 0

4 years ago