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Oxana [17]
3 years ago
7

A zip line runs from the top of a platform on the edge of a pond to the ground across the pond. A camp counselor places a mirror

on the edge of the pond across from the platform and stands back until the top of the platform is visible in the mirror. Use similar triangles to find the height of the platform.

Mathematics
1 answer:
tigry1 [53]3 years ago
3 0

Answer:

150 ft

Step-by-step explanation:

The diagram shown gives us a picture of two similar right triangle.

The height of the man is similar to the height of the platform.

To find the height of the platform, multiply the height of the man by the scale factor.

Scale factor = the ratio of any corresponding sides of two similar triangles.

Scale factor = 100 ft ÷ 4 ft = 25

Height of man = 6ft

Therefore, height of platform = 6 ft × 25 = 150 ft

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Mario went to a store and bought 3 slices of pizza. The guy at the register said " that would be $3.75". Mario then said "wait,
Zarrin [17]

Answer:

$5

Step-by-step explanation:

Cost per slice

3.75 / 3 = 1.25

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5 0
3 years ago
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Complete the steps 4/9 divided by 1/2
DedPeter [7]

Answer: 0.88 (the 8 recurs)

Step-by-step explanation:

\frac{4}{9}÷\frac{1}{2}

\frac{4}{9}×\frac{2}{1}  (Then the the fraction should reciprocal so the values should shift to          the opposite side were 2 goes up and 1 goes down and the sign turns to the multiplication sign)

then u should multiply the two fractions which gives 8/9

next you should divide 8 by 9 which gives 0.88(the number eight is recurring which means that the number 8 keeps repeating no matter how many times you try to divide)

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2 years ago
Enter the value that makes the given equation true. Y+396.23 =574.54
Levart [38]
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2 years ago
What is The Measurement of This angle
ZanzabumX [31]

Answer:

155°

Step-by-step explanation:

I think that because when you imagine it

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8 0
3 years ago
Find the laplace transform of f(t) = cosh kt = (e kt + e −kt)/2
iren2701 [21]
Hello there, hope I can help!

I assume you mean L\left\{\frac{ekt+e-kt}{2}\right\}
With that, let's begin

\frac{ekt+e-kt}{2}=\frac{ekt}{2}+\frac{e}{2}-\frac{kt}{2} \ \textgreater \  L\left\{\frac{ekt}{2}-\frac{kt}{2}+\frac{e}{2}\right\}

\mathrm{Use\:the\:linearity\:property\:of\:Laplace\:Transform}
\mathrm{For\:functions\:}f\left(t\right),\:g\left(t\right)\mathrm{\:and\:constants\:}a,\:b
L\left\{a\cdot f\left(t\right)+b\cdot g\left(t\right)\right\}=a\cdot L\left\{f\left(t\right)\right\}+b\cdot L\left\{g\left(t\right)\right\}
\frac{ek}{2}L\left\{t\right\}+L\left\{\frac{e}{2}\right\}-\frac{k}{2}L\left\{t\right\}

L\left\{t\right\} \ \textgreater \  \mathrm{Use\:Laplace\:Transform\:table}: \:L\left\{t\right\}=\frac{1}{s^2} \ \textgreater \  L\left\{t\right\}=\frac{1}{s^2}

L\left\{\frac{e}{2}\right\} \ \textgreater \  \mathrm{Use\:Laplace\:Transform\:table}: \:L\left\{a\right\}=\frac{a}{s} \ \textgreater \  L\left\{\frac{e}{2}\right\}=\frac{\frac{e}{2}}{s} \ \textgreater \  \frac{e}{2s}

\frac{ek}{2}\cdot \frac{1}{s^2}+\frac{e}{2s}-\frac{k}{2}\cdot \frac{1}{s^2}

\frac{ek}{2}\cdot \frac{1}{s^2}  \ \textgreater \  \mathrm{Multiply\:fractions}: \frac{a}{b}\cdot \frac{c}{d}=\frac{a\:\cdot \:c}{b\:\cdot \:d} \ \textgreater \  \frac{ek\cdot \:1}{2s^2} \ \textgreater \  \mathrm{Apply\:rule}\:1\cdot \:a=a
\frac{ek}{2s^2}

\frac{k}{2}\cdot \frac{1}{s^2} \ \textgreater \  \mathrm{Multiply\:fractions}: \frac{a}{b}\cdot \frac{c}{d}=\frac{a\:\cdot \:c}{b\:\cdot \:d} \ \textgreater \  \frac{k\cdot \:1}{2s^2} \ \textgreater \  \mathrm{Apply\:rule}\:1\cdot \:a=a
\frac{k}{2s^2}

\frac{ek}{2s^2}+\frac{e}{2s}-\frac{k}{2s^2}

Hope this helps!
3 0
3 years ago
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